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3 years ago

P: grass is green or Q: 3 is the square root of 10 (P ∨ Q)

2 answers:

4 0

P v Q is a disjunction, which is true whenever P or Q is true or both are true. P v Q is false only when P and Q are both false.

You know that Q is false, because 3 is not the square root of 10, so the only possibility for P v Q be true is that P is true.

If that is the case, you have this relation:

T F ---> T

which means True and False imply True

Zielflug [23.3K]3 years ago

3 0

Answer:

TFT

Step-by-step explanation:

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The exact value of cos5pi/12 is:

jonny [76]

Step 1: Convert $\frac{5\pi }{12}$ , which is in radians into degrees. To convert it multiply by $\frac{180}{\pi }$

$\frac{5\pi }{12} =\frac{180}{\pi }$

900/12

Step 2: 75 degrees isn't on the unit circle but 45 degrees and 30 degrees is. Since 45 + 30 = 75 you can use the cosine of 45 and 30 to find the exact value

cos45 = $\frac{\sqrt{2} }{2}$

cos30 = $\frac{\sqrt{3} }{2}$

Step 3: Add the cos45 and cos30 to get cos5pi/12

$\frac{\sqrt{2} }{2} +\frac{\sqrt{3} }{2} = \frac{\sqrt{2}+\sqrt{3}}{2}$

Hope this helped!

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2 years ago

if the interest rate is lower than the inflation rate, what happens for those who put money in a savings account.

Bas_tet [7]

Answer: Savers Lose

Step-by-step explanation: I had this question

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2 years ago

Solve for x math question

Colt1911 [192]

Square both sides

9(x + 2) = x + 4

Expand

9x + 18 = x + 4

Subtract x from both sides

9x + 18 - x = 4

Simplify 9x + 18 - x to 8x + 18

8x + 18 = 4

Subtract 18 from both sides

8x = 4 - 18

Simplify 4 - 18 to -14

8x = -14

Divide both sides by 8

x = -14/8

Simplify 14/8 to 7/4

C. x = -7/4

8 0

2 years ago

I need help with this question?????

nadezda [96]

Answer:

the other percentage is 3.96 equals 10.

Step-by-step explanation:

3 0

2 years ago

Identify the standard form of the equation by completing the square.

OLEGan [10]

Answer:

$\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Step-by-step explanation:

Given equation:

$4x^2-9y^2-8x+36y-68=0$

This is an equation for a horizontal hyperbola.

To complete the square for a hyperbola

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

$\implies 4x^2-8x-9y^2+36y=68$

Factor out the coefficient of the x² term and the y² term.

$\implies 4(x^2-2x)-9(y^2-4y)=68$

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

$\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36$

Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Therefore, this is the standard equation for a horizontal hyperbola with:

center = (1, 2)
vertices = (-2, 2) and (4, 2)
co-vertices = (1, 0) and (1, 4)
$\textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}$
$\textsf{Foci}: \quad (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)$

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1 year ago