(a+bi)(2+3i)-i=(-11+5i)(1-i)
2a+3ai+2bi+3bi²-i=-11+11i+5i-5i²
2a+(3a+2b-1)i-3b=-11+16i+5
(2a-3b)+(3a+2b-1)i=-6+16i
Therefore; we have the next system of equations:
2a-3b=-6
3a+2b-1=16
Finally, the system of equations is:
2a-3b=-6
3a+2b=17
We can solve this system of equations by reduction method
2(2a-3b=-6)
3(3a+2b=17)
----------------------
13a=39 ⇒a=39/13=3
3(2a-3b=-6)
-2(3a+2b=17)
----------------------
-13b=-52 ⇒ b=52/13=4
Answer: a=3; b=4
The answer would be √32 or 4√2 (which is simplified) because of pythagoras' theorem. If we substitute a = b = 4 into it, then c must equal the root of 16 + 16, or 32.
I guess it can be 2. If you're not looking for any zeros then the probable answer can most likely be 2
The price for senior citizens was 4 dollars and the price for the child tickets would be 7 dollars.
Answer:
A) Factor
Step-by-step explanation:
