Step-by-step explanation:
Hi there!
The given equation is:
y = -2x + 5………………(i)
Comparing the equation with y = mx+c, we get;
m1 = -2
Also another equation of the line which passes through point (-4,2), we get;
(y-2) = m2(X+4)............(ii) { using the formula (y-y1) = m2(x-x2)}
According to the question, they are perpendicular to eachother, So according to the condition of perpendicular lines;
m1*m2 = -1
-2*m2 = -1
or, m2 = 1/2.
Therefore, m2= 1/2.
Now, keeping the value of m2 in equation (ii).
(y-2) = 1/2(x+4)
y = (1/2)x + 4
Therefore, the required equation is: y = (1/2)x + 4.
<u>Hope</u><u> it</u><u> helps</u><u>!</u>
First you must have the quadratic equal to zero. In order to do this you must subtract 7 to both sides
x^2 + 20x + (100 - 7) = 7 - 7
x^2 + 20x + 93 = 0
Now you must find two numbers who's sum equals 20 and their multiplication equal 93
Are there any? NO!
This means that you have to use the formula:
In this case:
a = 1
b = 20
c = 93
^^^We must simplify √28
√28 = 2√7
so...
simplify further:
-10 + √7
or
-10 - √7
***plus/minus = ±
Hope this helped!
~Just a girl in love with Shawn Mendes
Solution:
The Point in the coordinate plane is A(-5,-4).
Perpendicular or shortest Distance from line y=3 that is (-5,3) to point (-5,-4) is
When it is reflected through the line, y=3, the coordinate of point A (-5,-4) changes to (-5,3+7)= B(-5,10).
Now, the Point B is translated by the rule , (x,y)—->(x+6,y),
So,the point B is translated to, (-5+6,10)=(1,10)
Option C: (1,10) is the glide reflection of point A(-5,-4).
Answer:
-2.26 lb
Step-by-step explanation:
Let the dog's initial weight be d.
Then, one year later, the dog weighs 3.73 lb less, and thus weighed d - 3.73 lb.
During the next year, the dog gained 1.47 lb, so now weighs d - 3.73 + 1.47 lb, or
d - 2.26 lb. This indicates a total weight loss of 2.26 over these two years.
Answer:
-15
Step-by-step explanation:
as i said if the signs are different the result is negative