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Mathematics

1 answer:

Luda [366]3 years ago

7 0

Answer:

400

Step-by-step explanation:

Multiply the whole number by the percentage. The number must be a decimal.

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Find the third term of (x^2 + 2)^4.

attashe74 [19]

Answer:

Step-by-step explanation:

$in~the~expansion~of~(x+a)^n\\T_{r+1}=ncr x^{n-r}a^r\\r+1=3\\r=3-1=2\\n=4\\4c2=\frac{4 \times 3}{2 \times 1} =6\\T_{2}=4(x^2)^{4-2}(2)^2\\=16(x^2)^2\\=16x^4$

7 0

3 years ago

Read 2 more answers

|18-x|, if x<18. Pls help

damaskus [11]

Answer:

I18 - xI such that x < 18.

ok, first let's what happens if x = 18:

I18 - xI = I18 - 18I = 0

So, at the moment we have the condition:

I18 - xI > 0.

now, if x is a really large negative number, suppose, x = -100

I18 + 100I = I118I = 118

So, as x can freely move in the negative range, we can see that I18 - xI can be any positive number, so the only restriction that we have is:

I18 - xI > 0.

This means that the domain is:

D = (-∞, 18)

and the range is:

R = (0, ∞)

3 0

3 years ago

Evaluate,

kirill [66]

With 10 to the power to a negative number, it's easier.
Here's a trick: The negative number is the places to the right of the decimal. The last number is a 1, while the rest are 0s.

From this, we get: $10^{-4}=\boxed{0.0001}$