Answer:
Step-by-step explanation:
The initial price of the swimsuit that Karla purchased at Amazon was 75.5
she use the coupon code to receive a 25% discount. This means that the value if the discount would be
25/100 × 75.5 = 0.25× 75.5 = 18.86
Therefore, the discounted price of the swimsuit is 75.5 - 18.875 = 56.625
The website applied a 10% service fee for the discount price. This means that the value of the service fee would be
10/100 × 56.625 = 0.1 × 56.625 = 5.6625.
The amount that Karla pays for the swimsuit would be
56.625 + 5.6625 = 62.2875
The difference between the original price and the price that Karla paid would be 75.5 - 62.2875 = 13.2125
The percentage by which the amount that Karla paid was lesser than the original price would be
13.2125/ 75.5 × 100 = 17.5%
Answer:
Tn = 2Tn-1 - Tn-2
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
If a17 = -40
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
(Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2
The recursive formula will be
Tn = 2Tn-1 - Tn-2
Answer:
Step-by-step explanation:
Answer:
San Carlos County
Step-by-step explanation:
a) Data and Calculations:
Number of cases of tuberculosis reported in the first half of 2001 = 17
Number of cases of tuberculosis reported in the second half = 18
Total number of cases reported = 35 (17 + 18)
Population of the county at the beginning of 2001 = 204,500
Population of the county at the end of the year = 215,000
Average population for the year = 209,750 (204,500 + 215,000)/2
Therefore, the incidence rate of tuberculosis in the county = 35/209,750 * 100
= 0.000167
b) Since the incidence rate is <1, it suggests that the population of San Carlos County is at a very reduced risk of exposure to tuberculosis. This means that only 1 in 6,000 (209,750/35) people are exposed to the disease in the county.
