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3 years ago

I'm going to cry please explain if ur good at math

Mathematics

1 answer:

Anton [14]3 years ago

3 0

Answer:

In the triangular prism calculator you can easily find out the volume of that solid. A general formula is volume = length * base_area; the one parameter you always need to have given is the prism length, and there are four ways to calculate the base - triangle area. Our triangular prism calculator has all of them implemented, isn't it awesome?

The specific formulas look as follows:

Length * Triangular base area given triangle base and height

It's this well-known formula mentioned before:

volume = length * 0.5 * b * h

Length * Triangular base area given three sides (SSS)

If you know the lengths of all sides, use the Heron's formula to find the area of triangular base:

volume = length * 0.25 * √( (a + b + c) * (-a + b + c) * (a - b + c) * (a + b - c) )

Length * Triangular base area given two sides and the angle between them (SAS)

You can calculate area of a triangle easily from trigonometry:

volume = length * 0.5 * a * b * sin(γ)

Length * Triangular base area given two angles and a side between them (ASA)

You can calculate that using trigonometry:

volume = = length * a² * sin(β) * sin(γ) / (2 * sin(β + γ))

Step-by-step explanation:

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#2 option: $\frac{2}{3}$

Step-by-step explanation:

$slope=\frac{rise}{run} =\frac{y^2-y^1}{x^2-x^1}$

$\frac{3-(-1)}{4-(-2)}=\frac{-4}{-6} =\frac{-2}{-3} =\frac{2}{3}$

= $\frac{2}{3}$

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2 years ago

Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno

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Answer:

a) P(X>np+3 $\sqrt{np(1-p)}$ =0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= $\sqrt{0.198}$ ≈ 0.445

a) P(X>np+3 $\sqrt{np(1-p)}$ =P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

$\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}$

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - $\frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}$ - $\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}$

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - $\frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)}$ - $\frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}$

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)= $\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}$ =0.349

P(Y>1)=1-0.349=0.651

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2 years ago