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Vinvika [58]
3 years ago
6

A builder is buying boxes of nails. She has $187 to spend and each box of nails costs $4. How many boxes of nails can the builde

r buy?
Mathematics
2 answers:
Sati [7]3 years ago
8 0
She can buy 46 and rests 3 bux
PolarNik [594]3 years ago
5 0
She can buy 46, when you divide 187 by 4 you get 46.75 or 46 (3/4).
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Evaluate each expression. 3^-2
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9 is the answer negatives cancel out creating positve
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What is the greatest common What is the greatest common divisor of 48, 60, 72, and 100?divisor of 48, 60, 72, and 100?
murzikaleks [220]

Answer:

4

Step-by-step explanation:

4is the right divisor because all of them are divisible by it

sorry i did a mistake earlier

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3 years ago
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A random sample of 100 people from City A has an average IQ of 120 with a SD of 18. Independently of this, a random sample of 15
Sloan [31]

Answer:

z=\frac{(120-116)-0}{\sqrt{\frac{18^2}{100}+\frac{15^2}{150}}}}=1.837

p_v =P(z>1.837)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the average IQ on city A is signficantly higher than city B at 5% of singificance.  

Step-by-step explanation:

\bar X_{A}=120 represent the mean for sample 1

\bar X_{B}=116 represent the mean for sample 2

s_{A}=18 represent the sample standard deviation for 1  

s_{B}=15 represent the sample standard deviation for 2  

n_{A}=100 sample size for the group 2  

n_{B}=150 sample size for the group 2  

\alpha Significance level provided

z would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if residents of City A smarter on average, the system of hypothesis would be:  

Null hypothesis:\mu_{A}-\mu_{B}\leq 0  

Alternative hypothesis:\mu_{A} - \mu_{B}> 0  

We don't have the population standard deviation's, but the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:  

z=\frac{(\bar X_{A}-\bar X_{B})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

z=\frac{(120-116)-0}{\sqrt{\frac{18^2}{100}+\frac{15^2}{150}}}}=1.837

P value

Since is a one right tailed test the p value would be:  

p_v =P(z>1.837)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the average IQ on city A is signficantly higher than city B at 5% of singificance.  

5 0
3 years ago
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ValentinkaMS [17]

Answer:

152.4 cm

Step-by-step explanation:

multiply the length value by 30.48

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Three hundred vehicles are parked in a parking garage. Seventy percent of the vehicles are midsized cars. What number of midsize
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210 cars are midsized
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