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2 years ago

7. Estimote the following percentages of 60. 10% = 25% = 50% = 20% =

Mathematics

2 answers:

Arlecino [84]2 years ago

5 0

Answer:

10% = 6

25% = 15

50% = 30

20% = 12

Step-by-step explanation:

10 % just drop the 0 from 60. 1/10 of 60 is 6

25% is 1/4. Divide: 60/4 =15

50% is half. Divide 60/2 = 30

20% is 1/5 Divide 60/5 =12

Orlov [11]2 years ago

3 0

Answer:

10% of 60 = 6

25% of 60 = 15

50% of 60 = 30

20% of 60 = 12

Step-by-step explanation:

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An isosceles triangle is such that each of the base angles is twice the vertical angle. find the angles of the triangle

frosja888 [35]

Answer:

2x + 2x + x =180
x = 36 degree

Step-by-step explanation:

6 0

1 year ago

A car with an initial cost of $26,500 depreciates at a rate of 7.5% per year. Write the function that models this situation. The

solniwko [45]

Answer:

f(x) = 26500 * (0.925)^x

It will take 7 years

Step-by-step explanation:

A car with an initial cost of $26,500 depreciates at a rate of 7.5% per year. Write the function that models this situation. Then use your formula to determine when the value of the car will be $15,000 to the nearest year.

To find the formula we will use this formula: f(x) = a * b^x. A is our initial value which in this case is $26500. B is how much the value is increasing or decreasing. In this case it is decreasing by 7.5% per year. Since the car value is decreasing we will subtract 0.075 from 1. This will result in the formula being f(x) = 26500 * (0.925)^x. Now to find the value of the car to the nearest year of when the car will be 15000 we plug 15000 into f(x). 15000 = 26500 * (0.925)^x. First we divide both side by 26500 which will make the equation: 0.56603773584=(0.925)^x. Then we will root 0.56603773584 by 0.925. This will result in x being 7.29968 which is approximately 7 years.

4 0

3 years ago

to make 1 batch of lavender paint the ratio of cups of pink paint to cups of blue paint is 6 to 5. find two more raios of cups o

marshall27 [118]

Your ratio is 6:5

This means that it is 6/5.

You have to find a common number to either divide or multiply that can work for both the numerator and denominator.

6/5 doesn't have any common number to divide without getting a remainder

But we can multiply by a common number such as 2

6×2 = 12
5×2 = 10

= 12/10. ☆= the ratio is 12 : 10

or even by 3, =the ratio 18:15

8 0

3 years ago

Read 2 more answers

I need help with pythagoras’ theorem

fomenos

Answer:

Pythagoras’ theorem is a way to find a side or hypothesis when you have 2 sides.

The formula is: a^2 + b^2 = c^2

a and b are sides

c is the hypothesis

<u>Ex: A triangle has a leg that is 5 inches and a leg that is 7 inches. Find the hypothesis using Pythagoras' theorem. </u>

A leg is another way of saying a side.

5^2 + 7^2 = c^2

25 + 49 = x^2

sqrt(74) = sqrt(x^2)

sqrt(74) inches = hypothesis

<u>Ex: A triangle has a leg that is 9 feet and a hypothesis that is 25 feet. Find the other leg using Pythagoras' theorem. </u>

9^2 + b^2 = 25^2

81 + b^2 - 81 = 625 - 81

sqrt(b^2) = sqrt(544)

b = sqrt(554)

Do you understand more?

4 0

3 years ago

Find the exact value of each trigonometric function for the given angle θ.

Kay [80]

Answer:

$\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.$

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since $\theta=240$ , it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

$\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}$

$\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}$

$\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}$

$\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}$

$\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2$

$\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}$

Therefore, $\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.$

8 0

3 years ago