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2 years ago

I have this one question I still dont get what 12/4 plus 12/5 is

Mathematics

1 answer:

zalisa [80]2 years ago

7 0

12/4 + 12/5 = the answer is 5.4

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What is the value of g(−3) when g(x)=2x−2 ?

denpristay [2]

g(x)=2x−2

g(-3) = 2(-3) -2

g(-3) = -6-2

g(-3) = -8

7 0

3 years ago

15.12 is what percent of 12?

Llana [10]

Answer:

Step-by-step explanation:

$\bold{METHOD\ 1}\\\\\begin{array}{ccc}15.12&-&p\%\\\\12&-&100\%\end{array}\qquad\text{cross multiply}\\\\\\12p=(15.12)(100)\\12p=1512\qquad\text{divide both sides by 12}\\p=126$

$\bold{METHOD\ 2}\\\\p\%=\dfrac{p}{100}\\\\p\%\ of\ 12\ is\ equal\ to\ 15.12:\\\\\dfrac{p}{100}\cdot12=15.12\\\\\dfrac{12p}{100}=15.12\qquad\text{multiply both sides by 100}\\\\12p=1512\qquad\text{divide both sides by 12}\\\\p=126$

6 0

3 years ago

The price of a cup of coffee was $2.65 yesterday. Today, the price fell to $2.30 . Find the percentage decrease. Round your answ

Semenov [28]

Percent change = change/original * 100
(2.65 - 2.30)/ 2.65 * 100
.35/2.65 * 100
13.2 % decrease
-13.2% if you need to write is as a negative

7 0

3 years ago

Ms. jones wants to take her students for all of her classes on a field trip to see a Broadway production. There are three shows

lina2011 [118]

Answer:

Step-by-step explanation:

Because it is a random sample

5 0

3 years ago

Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

$f(x) = \frac{3x-2}{x+1}$
$g(x)=x+5$
f[ -4 ] = ?
g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

$f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}$

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

$g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13$

Therefore, the value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0

2 years ago