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galina1969 [7]
3 years ago
15

Evaluate the expression for x = 2, y = -3, and z = -5. * 2x + 3y + z Your answer

Mathematics
2 answers:
Lunna [17]3 years ago
6 0
Plug in

2(2) + 3(-3) + (-5)
4 + (-9) + (-5)
4 + (-14)
-10

Answer is -10
2x + 3y + z = -10
algol133 years ago
6 0

Answer:

-10

Step-by-step explanation:

replace each letter with each number given, like shown below.

2(2)+3(-3)+(-5)

= 4+-9+-5

= -5+-5

= -10

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Solve for x.<br> 5. 150 - (2x + 90) = 4x
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Then do 150-90 which will result in 60-2x=4x.

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4 years ago
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Rectangle JKLM:J(-3, 8), K(-3,-1), L(4, -1),
Maslowich

Answer:

The perimeter of the Rectangle JKLM is 32 unit.

Step-by-step explanation:

Consider the provided coordinates.

Rectangle JKLM: J(-3, 8), K(-3,-1), L(4, -1),  M(4,8)

First plot the points as shown in figure:

The required figure is shown below:

Now find the distance between JK by using the distance formula.

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

d=\sqrt{\left(-3-\left(-3\right)\right)^2+\left(-1-8\right)^2}=9

Therefore, the length of JK is 9 unit.

Now find the length of the side JM

d=\sqrt{\left(4-\left(-3\right)\right)^2+\left(8-8\right)^2}=7

Therefore, the length of JM is 7 unit.

The perimeter of rectangle is: P=2(l+b)

Therefore,

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Hence, the perimeter of the Rectangle JKLM is 32 unit.

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