Given:
Length = x + x + 3 = 2x + 3
Width = 2 + x
Area = length * width
91 ft² = (2x + 3) (2+x)
91 = 4x + 2x² + 6 + 3x
0 = 2x² + 7x + 6 - 91
0 = 2x² + 7x - 85
(2x + 17) ( x - 5)
x = -17/2 or x = 5
Let x = 5 ;
length = 2x + 3 = 2(5) + 3 = 13
width = 2 + x = 2 + 5 = 7
Area = 13 x 7 = 91
Perimeter = 2(length + width)
Perimeter = 2(13 + 7)
Perimeter = 2(20)
Perimeter = 20 feet of fencing
Answer:
![=8\left(2a+9\right)](https://tex.z-dn.net/?f=%3D8%5Cleft%282a%2B9%5Cright%29)
Step-by-step explanation:
![16a+72](https://tex.z-dn.net/?f=16a%2B72)
![\mathrm{Rewrite\:}16\mathrm{\:as\:}8\cdot \:2](https://tex.z-dn.net/?f=%5Cmathrm%7BRewrite%5C%3A%7D16%5Cmathrm%7B%5C%3Aas%5C%3A%7D8%5Ccdot%20%5C%3A2)
![\mathrm{Rewrite\:}72\mathrm{\:as\:}8\cdot \:9](https://tex.z-dn.net/?f=%5Cmathrm%7BRewrite%5C%3A%7D72%5Cmathrm%7B%5C%3Aas%5C%3A%7D8%5Ccdot%20%5C%3A9)
![=8\cdot \:2a+8\cdot \:9](https://tex.z-dn.net/?f=%3D8%5Ccdot%20%5C%3A2a%2B8%5Ccdot%20%5C%3A9)
![\mathrm{Factor\:out\:common\:term\:}8](https://tex.z-dn.net/?f=%5Cmathrm%7BFactor%5C%3Aout%5C%3Acommon%5C%3Aterm%5C%3A%7D8)
![=8\left(2a+9\right)](https://tex.z-dn.net/?f=%3D8%5Cleft%282a%2B9%5Cright%29)
Hence, the correct answer is ![=8\left(2a+9\right)](https://tex.z-dn.net/?f=%3D8%5Cleft%282a%2B9%5Cright%29)
Answer:
n=0 n=20
Step-by-step explanation:
2n(n-20) =0
Using the zero product property, set each factor to zero
2n =0 n-20 =0
Solve each equation
2n/2 =0/2 n-20+20 =0+20
n=0 n=20
Depends on what your trying to measure !!!