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dimulka [17.4K]
3 years ago
6

7.3 x 10^5 + 3.7 x 10^5=

Mathematics
1 answer:
Scilla [17]3 years ago
5 0

Answer:

1100000

Step-by-step explanation:

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Find the length of the arc round your answer to the nearest 10th
son4ous [18]

Answer:

Step-by-step explanation:

3 0
3 years ago
J'K'L'M' is a translation of JKLM by vector (-6/2). What are the coordinates of K'? What are the coordinates of M'?
pochemuha

By applying the concept of <em>rigid</em> transformation and the equation of translation we conclude that the coordinates of points K' and M' are (-2, 3) and (-4, 1).

<h3>How to apply a translation to a point on a Cartesian plane</h3>

<em>Rigid</em> transformations are transformations applied onto <em>geometric</em> loci such that Euclidean distance is conserved at every point of the loci. Translations are an example of <em>rigid</em> transformations, whose formula is defined by the following expression:

P'(x, y) = P(x, y) + \vec v     (1)

Where:

  • P(x, y) - Original point
  • P'(x, y) - Resulting point
  • \vec v - Translation vector

If we know that K(x, y) = (4, 1), M(x, y) = (2, -1) and \vec v = (-6, 2), then the coordinates of points K' and M' are:

Point K'

K'(x, y) = (4, 1) + (-6, 2)

K'(x, y) = (-2, 3)

Point M'

M'(x, y) = (2, -1) + (-6, 2)

M'(x, y) = (-4, 1)

By applying the concept of <em>rigid</em> transformation and the equation of translation we conclude that the coordinates of points K' and M' are (-2, 3) and (-4, 1).

To learn more on translations: brainly.com/question/17485121

#SPJ1

7 0
1 year ago
Which of the following word problems can be solved using the equation 4(x + 8) = 40?
Black_prince [1.1K]

Answer:

the answer is a because ots increased by 8 inches

3 0
3 years ago
Translate this problem to an equation and solve. The product of 2 positive consecutive even integers is 48. What is the smaller
bonufazy [111]
Let x represent the first even integer: x = 2(k) → y = 2k
Let y represent the second even integer: y = 2(k + 1)  → y = 2k + 2

   x  ·     y        = 48
(2k) · (2k + 2) = 48
 4k² + 4k - 48  = 0
 4(k² + k - 12)  = 0
4 (k + 3)(k - 2) = 0
k = -3, k = 2  (Note: POSITIVE integers so k = -3 is ruled out)

x = 2k → x = 2(2) → x = 4
y = 2(k + 1) → y = 2(2 + 1) → y = 2(3) → y = 6

The smaller number (x) is 4
        


8 0
3 years ago
Consider the initial value problem y′′+36y=2cos(6t),y(0)=0,y′(0)=0. y″+36y=2cos⁡(6t),y(0)=0,y′(0)=0. Take the Laplace transform
Bingel [31]

Recall the Laplace transform of a second-order derivative,

L(y''(t)) = s^2Y(s)-sy(0)-y'(0)

and the transform of cosine,

L(\cos(at))=\dfrac s{a^2+s^2}

Here, both y(0)=y'(0)=0, so taking the transform of both sides of

y''(t)+36y(t)=2\cos(6t)

gives

s^2Y(s)+36Y(s)=\dfrac{2s}{36+s^2}

\implies Y(s)=\dfrac{2s}{(s^2+36)^2}

4 0
3 years ago
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