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3 years ago

Which of the following predictions is most likely true

Mathematics

2 answers:

Sunny_sXe [5.5K]3 years ago

5 0

Your answer is D because 10*2 is 20 and 6*2 is 12 so 12 out of the next 20 customers will purchase a sandwich.

Pani-rosa [81]3 years ago

5 0

D.

6 out of 10 is equivalent to 12 out of 20

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A map has a scale of 1cm:20 km two cities are 2.5 cm apart on the map to the nearest tenth of a kilometer what is the actual dis

Aleksandr-060686 [28]

Answer: 50 km

Step-by-step explanation: So the map has a scale of 1 cm: 20 km. Next, you look at how far they are apart and see if the scale and the distance on the map are the same measurement. In this case, they are both centimeters so they stay the same. Then, all you do is multiple the real size, 20 km, by

2.5 /1 . Then, 20 x 2.5=50. So the answer is 50 km

6 0

3 years ago

The bill is $100.99. You want to leave a 20% tip. How much should the tip be?

Arisa [49]

Answer:

$20.20

Step-by-step explanation:

First Convert 20% into a decimal, by dividing it by 100

Percent = out of 100

20/100 = 0.2

Now, multiply the decimal (0.2) with the bill amount ($100.99):

0.2*100.99

$20.198 <== *remember, we are using money, so we round to the nearest cent (dime)

$20.20 <== how much tip you want to leave

How much you pay altogether:

(Bill + tip)

100.99 + 20.20

$121.19

Hope this helps!

8 0

2 years ago

The expression, involving exponents , to represent the shaded area, in square inches, diagram. Then use that expression to calcu

mart [117]

Answer:

The shaded area is $23\ in^{2}$

Step-by-step explanation:

we know that

The shaded area is equal to the area of the large square minus the area of the two smaller squares

$A=6^{2} -(3^{2} +2^{2})\\ \\ A=(2*3)^{2} -(3^{2} +2^{2})\\ \\A=(2^{2})(3^{2}) -(3^{2} +2^{2})$

Calculate the shaded area

Remember that

$3^{2}=9\\ 2^{2}=4$

substitute

$A=(4)(9) -(9 +4)\\ \\A=36-13\\ \\A=23\ in^{2}$

5 0

3 years ago

Please help me with this question!

gavmur [86]

First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway thus

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{first sol'n}&11&x&11x\\
\textit{second sol'n}&4&0.55&2.20\\
------&-----&-------&-------\\
mixture&y&0.77&0.77y
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
11+4=y\implies 15=\boxed{y}\\
11x+2.2=0.77y\\
----------\\
11x+2.2=0.77\cdot \boxed{15}
\end{cases}$

solve for "x"

6 0

3 years ago

Ted needs an average of at least 70 on his three history test he has scored already 85 and 60 on two test what is the minimum gr

PilotLPTM [1.2K]

So average=(total of scores)/(number of tests)
needs at least average of 70
at least is represented as greater than or equal to or the sign (>)
70>(total)/(number oftests)

since we have 3 tests, we have to have 3 scores so
70>(x+y+z)/3
he scored 85 and 60
70>(x+85+60)/3 (doesn't matter which to subsitute)
70>(x+145)/3
multiply obht sides by 3
210>x+145
subtract 145 from both sides
65>x
he needs to get at leas 65 on his third test

4 0

3 years ago