<span>1.Verify whether n is large enough to use the normal approximation by checking the two appropriate conditions.
<span>2.Translate the problem into a probability statement about X.</span></span>
40 x 10 = 400
400 / 100 = 4
Mai has 4 hundreds.
<h3>
Answer: y = 10</h3>
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Work Shown:
EI = EG
3y-10 = 2y
3y-10-2y = 0
y-10 = 0
y = 0+10
y = 10
Note how if y = 10, then
- EI = 3y-10 = 3*10-10 = 20
- EG = 2y = 2*10 = 20
Both EI and EG are 20 units long when y = 10. This confirms the answer.
So fuctions mean
if
f(x)=x+2 then if you put in 3 for x then
f(3)=3+2=5 so
if x=years after 2000
in 2020 then
2020-2000=20 so x=20
subsitute
f(20)=9204e^0.022(20)
e could be:
1. common base of logarithms (memorised to 15 decmals) 2.718281828459045
2. a computer notation exg if you have 3e11 that means 3 times 10^11
if it is 1
9240 times (2.718281828459045^(0.022 times 20))=( simplify exponent first) 9240 times (2.718281828459045^0.44)=9204 times 1.5527072185113=14291.1 or rounded to 14291
if it is 2
9204 times 10^(0.022 times 20)=9204 times 10^(0.44)=9204 times 254.491 rounded to 254
so the answer dependes on what e represents,
if e is:
1. common base of logarithms (memorised to 15 decmals) 2.718281828459045, then answer is 14291
2. a computer notation exg if you have 3e11 that means 3 times 10^11 =254
C. Infinitely many of solutions
