Simple....
you have:
3x-9=7x+12
To even solve this....isolate the variable your are trying to solve for....
3x-9=7x+12
-3x -3x
-9=4x+12
-9=4x+12
-12 -12
-21=4x
Simplify.....
Thus, your answer.
The answer to your question is 6 3/8.
It took 14 minutes
70 degrees +(14minutes times 20degrees) = 350 degrees.
:)
For a polyonomial
P(x)=ax^n+bx^(n-1)...zx^0
when n is odd, the endpoints of the graph point in oposite directions
when n is even, the endpoints of the graph point in same direction
a is the leading term
when a is positive and:
1. n is odd, the graph goes from bottom left to top right
2. n is even, the graph goes from top left to top right
when a is negative and:
1. n is odd, the graph goes from top left to bottom right
2. n is even, the graph goes from bottom left to bottom right
xintercept is where the line crosses the x axis or when y=0
yintercept is where the line crosses the y axis or when x=0
f(x)=1x^3-11x^2+36x-36
leading term is positive and odd degree
graph goes from bottom left to top right, has 1 inflection point
yint, sub 0 for all x's
f(0)=0^3-11(0)^2+36(0)-36
yintercept is y=-36 or (0,-36)
xintercept
set function equal to zero
0=x^3-11x^2+36x-36
factor
0=(x-2)(x-3)(x-6)
x=2,3,6
xintercepts are at x=2,3,6 or (2,0), (3,0) and (6,0)
3. I believe the answer is C & A, arrange the boards so that the diagonals bisects and are perpendicular. A rhombus is a Quadrilateral with all its sides equal to each other. The diagonals of a rhombus are perpendicular to each other and bisects each other.
4.The corresponding pairs of base angles of a trapezoid add up to 180 degrees, (they are supplementary), While all the angles (the four angles add up to 360 degrees)
Therefore; in this case the two angles are equal
hence, 19x + 8 = 11x+16 solving for x
x = 1
substituting x in either of the expression
The angle = 27 °
5. The diagonals of a rhombus bisects each other at right angles; the are perpendicular,
hence,
m∠1= 10x = 90
x = 9
m∠2 = x + y =90
but x = 9,
thus, y = 81
m∠3 = 5z= 90
z =18
10. A kite is a Quadrilateral with two equal sides and the other two sides equal.
thus, y-4 = 5x+2 and x +22 = 3x +10
solving for x
x+22 = 3x +10
2x = 12
x = 6
y-4 = 5x +2
y-4 = 5(6) +2
y = 36.
11.a. RHOM is a Quadrilateral with four equal sides
b. The four sides RH, OH, OM, and RM are equal, They are all congruent
c HM and HM is the diagonal, which forms the corresponding sides of triangle MRH and triangle MOH
d. Triangle MRH and triangle MOH are congruent, SSS, and similar to each other.
