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rjkz [21]
3 years ago
5

Pls help me asap!!! ​

Mathematics
1 answer:
shusha [124]3 years ago
3 0

Answer:

I think 6 1/2? srry if wrong

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A grocery store sells a bag of 6 oranges for $2.34. If Mav spent $1.95 on oranges, how many did she buy?
poizon [28]

Answer:

5 oranges

Step-by-step explanation:

to solve this problem we need to make a cross-multiplication equation

2.34 is to 6 as 1.95 is to ?

? is the number of oranges that are needed to be found that were bought

2.34/6 = 1.95/?

Now we cross multiply 6 and 1.95 = 11.7

11.7/2.34 = 5

Give brainliest, please!
hope this helps :)

5 0
2 years ago
Read 2 more answers
For most answers, you will simply enter your numeric answer directly into the space provided to the right of the equal sign. Ans
Vedmedyk [2.9K]

Answer:

12 dozens of eggs I believe

Step-by-step explanation:

12 eggs are in one dozen

<em>Divide</em><em> </em><em>1</em><em>4</em><em>4</em><em> </em><em>by</em><em> </em><em>1</em><em>2</em><em>. </em><em> </em><u>1</u><u>4</u><u>4</u><u>÷</u><u>1</u><u>2</u><u>=</u><u>1</u><u>2</u>

4 0
4 years ago
A carnival ride is in the shape of a wheel with a radius of 25 feet. The wheel has 20 cars attached to the center of the wheel.
Vladimir79 [104]

Centre angle will be 360° as its totally a circle.

  • radius=r=25ft

Angle between two cars=360/20=18°

  • Arc length=L

\\ \sf\longmapsto L=\dfrac{\theta}{360}(2\pi r)

\\ \sf\longmapsto L=\dfrac{18}{360}(2\pi(25))

\\ \sf\longmapsto L=\dfrac{1}{20}(50\pi)

\\ \sf\longmapsto L=2.5\pi ft

Now

Area be A

\\ \sf\longmapsto A=\dfrac{1}{2}Lr^2

\\ \sf\longmapsto A=\dfrac{1}{2}(2.5\pi)(25)^2

\\ \sf\longmapsto A=625(2.5)\pi\dfrac{1}{2}

\\ \sf\longmapsto A=1562.5\pi/2

\\ \sf\longmapsto A=781\pi ft^2=

4 0
3 years ago
Determine whether the following statement is a tautology, contradiction, or neither (~PVQ) ~Q Tautology Contradiction • Neither
Tom [10]

Answer:

The statement (\lnot P \lor Q)\rightarrow \lnot Q is neither a tautology nor a contradiction.

Step-by-step explanation:

A tautology is a statement that is always true.

A contradiction is a statement that is always false.

We are going to use a truth table to determine whether the statement (\lnot P \lor Q)\rightarrow \lnot Q is a tautology, contradiction, or neither

A truth table shows how the truth or falsity of a compound statement depends on the truth or falsity of the simple statements from which it's constructed.

The statement (\lnot P \lor Q)\rightarrow \lnot Q is compound by these simple statements:

  • \lnot P
  • \lnot Q
  • (\lnot P \lor Q)

and we are going to use these simple statements to build the truth table.

The last column contains true and false values. Therefore, the statement is neither a tautology nor a contradiction.

6 0
4 years ago
A particle in the first quadrant is moving along a path described by the equation LaTeX: x^2+xy+2y^2=16x 2 + x y + 2 y 2 = 16 su
ElenaW [278]

Answer:

\frac{50}{3} cm/sec.

Step-by-step explanation:

We have been given that a particle in the first quadrant is moving along a path described by the equation x^2+xy+2y^2=16 such that at the moment its x-coordinate is 2, its y-coordinate is decreasing at a rate of 10 cm/sec. We are asked to find the rate at which x-coordinate is changing at that time.

First of all, we will find the y value, when x =2 by substituting x =2 in our given equation.

2^2+2y+2y^2=16

4-16+2y+2y^2=16-16

2y^2+2y-12=0

y^2+y-6=0

y^2+3y-2y-6=0  

(y+3)(y-2)=0

(y+3)=0,(y-2)=0

y=-3,y=2

Since the particle is moving in the 1st quadrant, so the value of y will be positive that is y=2.

Now, we will find the derivative of our given equation.

2x\cdot x'+x'y+xy'+4y\cdot y'=0

We have been given that y=2, x =2 and y'=-10.

2(2)\cdot x'+(2)x'+2(-10)+4(2)\cdot (-10)=0

4\cdot x'+2x'-20-80=0

6x'-100=0

6x'-100+100=0+100

6x'=100

\frac{6x'}{6}=\frac{100}{6}

x'=\frac{50}{3}

Therefore, the x-coordinate is increasing at a rate of \frac{50}{3} cm/sec.

7 0
3 years ago
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