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Allisa [31]
2 years ago
5

Please help me answer this (image)

Mathematics
2 answers:
lisov135 [29]2 years ago
7 0
<h3>Answer:  416 cubic mm</h3>

Work Shown:

V = lwh

V = 10.4*5*8

V = 416

Explanation: We multiply the length, width, and height to get the volume of the block. The units for the volume are in cubic millimeters which can be written as "cubic mm" or \text{mm}^3 to mean that we're cubing all of "mm", and not just a single m.

I guess you could say  (\text{mm})^3 to be very clear that both "m"s are being cubed, though this convention isn't something I've seen a lot.

soldi70 [24.7K]2 years ago
4 0
V= l*w*h
416 is your ans
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Sedaia [141]

Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24

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<em />

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