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Allisa [31]
2 years ago
5

Please help me answer this (image)

Mathematics
2 answers:
lisov135 [29]2 years ago
7 0
<h3>Answer:  416 cubic mm</h3>

Work Shown:

V = lwh

V = 10.4*5*8

V = 416

Explanation: We multiply the length, width, and height to get the volume of the block. The units for the volume are in cubic millimeters which can be written as "cubic mm" or \text{mm}^3 to mean that we're cubing all of "mm", and not just a single m.

I guess you could say  (\text{mm})^3 to be very clear that both "m"s are being cubed, though this convention isn't something I've seen a lot.

soldi70 [24.7K]2 years ago
4 0
V= l*w*h
416 is your ans
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Answer:

y^35

Step-by-step explanation:

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2 years ago
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< the bigger number is facing the back of the arrow it points to the smaller number Example: 1<2
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3 years ago
A square has an area of 49 cm2. what is the length of each side?​
Deffense [45]

Answer: 24.5

Step-by-step explanation:

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3 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
2 years ago
19. The product of two consecutive integers is 5 more than three times the larger
dusya [7]
X = larger number
x-1 = smaller number

x*(x-1)=5+3x

x^2-4x-5=0 use the formula

x=5
x-1=4
the 2 numbers are 5&4 or -1,-2


6 0
2 years ago
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