Please help me answer this (image)

Mathematics

2 answers:

lisov135 [29]2 years ago

7 0

<h3>Answer: 416 cubic mm</h3>

Work Shown:

V = lwh

V = 10.4*5*8

V = 416

Explanation: We multiply the length, width, and height to get the volume of the block. The units for the volume are in cubic millimeters which can be written as "cubic mm" or $\text{mm}^3$ to mean that we're cubing all of "mm", and not just a single m.

I guess you could say $(\text{mm})^3$ to be very clear that both "m"s are being cubed, though this convention isn't something I've seen a lot.

soldi70 [24.7K]2 years ago

4 0

V= l*w*h
416 is your ans

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Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24$