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4 years ago

What risks, threats, and vulnerabilities are prominent with wlan infrastructures?

1 answer:

4 0

The threats as well as the risk and vulnerabilities are present with the WLAN. The WLAN would encounter security issues with the range of the signal which is wireless, SSID broadcasting, password security and the packet sniffing or the capturing of signal.

You might be interested in

Which would you use to get the number of elements in a dictionary?

Vikentia [17]

The function use to get the number of element in a dictionary is len.

<h3>What is a dictionary?</h3>

Dictionaries are used to store data values in key-value pairs. Dictionary are ordered.

Dictionary in python are express as follows:

my_dict = {"name": "Michael", "age": 28, "school": "Oxford"}

Therefore, the length of the element of the dictionary can be gotten using the len() function.

Hence,

print(len(my_dict)) will give you the length of the element.

learn more on dictionary here: brainly.com/question/14120893

#SPJ11

8 0

2 years ago

Which sequence represents the hierarchy of terms, from smallest to greatest?

Anni [7]

Answer:

Explanation:

7 0

3 years ago

Write a function named “createPurchaseOrder” that accepts the quantity (integer), the cost per item(double), and the description

Leona [35]

#include
Program: using namespace std;
string createPurchaseOrder0;
int main(
{
cout<return 0;
}
string createPurchaseOrder(
{
int qty;
double costPerltem;
string description,info="":
cout<<"Enter Quantity:
cin>>qty;
cout<<"Enter cost per item: "
cin>>costPerltem;
cout<<"Enter Description: "
cin>>description;
if(qty<0 I| costPerltem<0
Idescription.compare(''"')==0)
cout<<'InThe entered data is invalid!":
info="":
else
"
cout<<"'InThe entered data is valid!":
info=info+"'(nQuantity: "+to_string (qty) +" In";
info=info+"Cost per item:
"†to_string (costPerltem)+"In";
info=info+"Description: "description+" In";
return info;

Output:

4 0

3 years ago

a password to a certain database consists of digits that cannot be repeated. if the password is known to consist of at least 8 d

BaLLatris [955]

Answer:

$\frac{10!}{2}mins$

Explanation:

12 seconds to try one combination will be equivalent to $\frac{1}{12}\times 60 = \frac{1}{5} \ mins$

Password contain at least 8 digit i.e. password can contain 8, 9, 10 digit.

Password cannot contain more than 10 digit because it will give room for repetition which it is clearly stated that digit cannot be repeated.

Possible digit that can be used: 9,8,7,6,5,4,3,2,1,0.

Total number of passwords combination possible for each position in 8 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3. Total number of passwords combination possible in 8 digit is equivalent to $\frac{10!}{2}$ .

Total number of passwords combination possible for each position in 9 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2. Total number of passwords combination possible in 9 digit is equivalent to $\frac{10!}{1}$ .

Total number of passwords combination possible for each position in 10 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2, 10th position = 1. Total number of passwords combination possible in 10 digit is equivalent to 10!.

Adding them up and multiplying by $\frac{1}{5} \ mins$ to get the total number of time needed to guarantee access to database = $[\frac{10!}{2}\times\ \frac{10!}{1} \times 10!] \frac{1}{5}\ mins = \frac{10!}{2}$

7 0

3 years ago

Write a program that helps a young student learn to make change. Use the random number generator to generate change amounts betw

erastovalidia [21]

Answer:

#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

int quarters = coins/25;

coins = coins%25;

int dimes = coins/10;

coins = coins%10;

int nickles = coins/5;

coins = coins%5;

int pennies = coins/1;

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

}

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

int quarters = coins/25;

coins = coins%25;

int dimes = coins/10;

coins = coins%10;

int nickles = coins/5;

coins = coins%5;

int pennies = coins/1;

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

}

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}

Explanation:

Use the built-in rand function to generate a random coin.
Get all the required values for quarters, dimes, nickles and pennies and store them in variables.
Check if the coins give a value of temp, then answer is correct and the values of user will be added.
Optimum solution is displayed If it does not matches with the optimum solution. Display that the answer is wrong along with solution.

6 0

3 years ago