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grigory [225]
3 years ago
7

What risks, threats, and vulnerabilities are prominent with wlan infrastructures?

Computers and Technology
1 answer:
vovangra [49]3 years ago
4 0
The threats as well as the risk and vulnerabilities are present with the WLAN. The WLAN would encounter security issues with the range of the signal which is wireless, SSID broadcasting, password security and the packet sniffing or the capturing of signal.
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What is a variable?
aleksandr82 [10.1K]
Answer. D: a value that looks loads when the program runs.


Explanation:

In programming, a variable is a value that can change, depending on conditions or on information passed to the program. Typically, a program consists of instruction s that tell the computer what to do and data that the program uses when it is running.
5 0
3 years ago
Many company websites are now designed to do more than just sell a product. These​ websites, known as​ __________ websites, atte
Zinaida [17]

Answer:

brand community

Explanation:

Many company websites are now designed to do more than just sell a product. These​ websites, known as​ brand community websites, attempt to build closer customer relationships and generate engagement with and between the brand and its customers. These online communities bring together consumers who have shared interests in a brand or product. One advantage of online brand communities is that they reduce customer support costs as the business has more engagement with their customers.This also helps the business to retain customers through brand improvement centered around the customer's actual needs.

5 0
3 years ago
Which of the following is not a technology that can be used to conserve resources?
amm1812
<span>Natural gas when extracted through human industry will utilise resources to construct the necessary plant and machinery and then result in the consumption of a resource. Therefore this is the technology that cannot be seen as conserving resources.</span>
6 0
3 years ago
Read 2 more answers
In c++
Elodia [21]

Answer:

class studentType: public personType

{

public:

virtual void print() = 0;

virtual void calculateGPA() = 0;

void setID(long id) {

studentId = id;

}

void setCourses(const string c[], int noOfC) {

noOfCourses = noOfC;

for (int i=0; i<noOfCourses; i++) {

courses[i] = c[i];

}

}

void setGrades(const char cG[], int noOfC) {

noOfCourses = noOfC;

for (int i=0; i<noOfCourses; i++) {

coursesGrade[i] = cG[i];

}

}

long getID() {

return studentId;

}

string* getCourses() {

return courses;

}

char* getGrades() {

return coursesGrade;

}

studentType(string fName = "", string lastName = "",

long id = 0, string c[] = NULL, char cG[] = NULL, int noOfC = 0);

private:

long studentId;

string courses[6];

char coursesGrade[6];

int noOfCourses;

};

Explanation:

Code rewritten

5 0
3 years ago
Create an array to hold the rainfall values. Create a 2nd parallel array (as a constant) to hold the abbreviated names of the mo
Zarrin [17]

Answer:

#include <stdio.h>

int main()

{

//variable declaration

int low, high;

float lowRain, highRain, total, avg;

 

//array declaration

float rainfall[13];

char monthName[13][10] = {"", "Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"};

//get user input

for(int i=1; i<=12; i++)

{

printf("Enter the rainfall (in inches) for %s: ", monthName[i]);

scanf("%f", &rainfall[i]);

}

 

//display the monthly rainfall

printf("\nThe rainfall that was entered was:\n");

for(int i = 1; i<=6; i++)

printf("%s ", monthName[i]);

printf("\n");

for(int i = 1; i<=6; i++)

printf("%.1f ", rainfall[i]);

printf("\n");

for(int i = 7; i<=12; i++)

printf("%s ", monthName[i]);

printf("\n");

for(int i = 7; i<=12; i++)

printf("%.1f ", rainfall[i]);

 

//variable initialization

low = 1;

high = 1;

lowRain = rainfall[1];

highRain = rainfall[1];

total = 0;

 

//calculate the lowest, highest and averaage rainfall

for(int i=1; i<=12; i++)

{

if(lowRain>rainfall[i])

{

lowRain = rainfall[i];

low = i;

}

if(highRain<rainfall[i])

{

highRain = rainfall[i];

high = i;

}

total = total + rainfall[i];

}

 

avg = total / 12;

 

//display the result

printf("\n\nThe total rain that fell was %.1f inches", total);

printf("\nThe average monthly rainfall was %.1f inches.", avg);

printf("\nThe lowest monthly rainfall was %.1f inches in %s.", rainfall[low], monthName[low]);

printf("\nThe highest monthly rainfall was %.1f inches in %s.", rainfall[high], monthName[high]);

return 0;

}

4 0
3 years ago
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