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USPshnik [31]
3 years ago
5

Which of these expressions is equivalent to -2(x-5)?

Mathematics
1 answer:
Serga [27]3 years ago
4 0

Answer:

The answer is -2x+10

Step-by-step explanation:

Hope this helps

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Can someone tell me what the answer for <br> 2 kos60° + tan 45 ° ​
enot [183]

Answer:

{ \tt{2 \cos60 \degree +  \tan(45 \degree) }} \\  \\  = 2(0.5) + 1 \\  = 1 + 1 \\  = 2

8 0
3 years ago
PLSSS HELP IF YOU TURLY KNOW THISSS
Nana76 [90]

Answer:

3

Step-by-step explanation:

Using the rule of exponents

a^{m} ÷ a^{n} = a^{(m-n)} , then

12^{6} ÷ 12^{3} = 12^{(6-3)} = 12³

4 0
3 years ago
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Graph x &gt; -3x&gt;−3x, is greater than, minus, 3.
antiseptic1488 [7]
It just is :). Ok ok
4 0
3 years ago
Need help with this assoon as possible
frez [133]
10(x/2 + 8) = 11, expand

10x/2 + 80 = 11

5x/2 = 11-80= -69
5x = -138
x = - 138/5




4 0
3 years ago
A portfolio has a E[r] of 12% and a std deviation of 18%. T-Bills return 7%. What is the maximum level of risk aversion (A) for
solniwko [45]
<h2>The required "option D) 3.09" is correct.</h2>

Step-by-step explanation:

Given,

A portfolio has a E[r] = 12 %, and

A standard deviation (\sigma) = 18 %

We know that,

Specify utility by U = E(r) – 0.5A\sigma^2

U = 0.12– 0.5(A) × 0.18^2

= 0.12 - 0.5  ×  A × 0.0162

In order for the risky portfolio to be preferred to bills,

The following condition must have:

0.12 – 0.0162A > 0.07

⇒ A < \dfrac{0.05}{0.0162} = 3.09

A must be less than 3.09 for the risky portfolio to be preferred to bills.

Thus, the required "option D) 3.09" is correct.

8 0
3 years ago
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