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malfutka [58]
3 years ago
13

-8+20 use the number line to justify your answer

Mathematics
1 answer:
Nana76 [90]3 years ago
7 0

Answer:

12

Step-by-step explanation:

Start at negative 8 on the number line than move to positive 20

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I need immediate help
Greeley [361]

Answer:

when we put 1 from a2 we can say that a2 equal to 2 because 2.5^n-1= 2

Step-by-step explanation:

answer is b

7 0
3 years ago
PLEASE HELP 20+ POINTS!! What is the cosine equation of the function shown?
noname [10]

Answer:   \bold{y=7\ \cos\bigg(x-\dfrac{\pi}{4}\bigg)-4}

<u>Step-by-step explanation:</u>

y = A cos (Bx - C) + D

  • A (amplitude) = max - D
  • B = Period/2π  --->   Period is the distance from max to next max
  • C = B · Phase Shift  ---> Phase shift is distance from y-axis to max
  • D (vertical shift) = (max + min)/2

D = (max + min)/2     =     (3 - 11)/3      =  -4

A = max - D               =     3 - (-4)         = 7

Period = 9π/4 - π/4   =    8π/4            = 2π

B = Period/2π           =    2π/2π          = 1

Phase Shift = π/4 - 0 =     π/4

C = B · Phase Shift    =  1 · π/4            = π/4

Equation:

           y = 7 cos (1·x - π/4) + (-4)

               

8 0
3 years ago
Choose ASA SAA or neither to describe this figure
ololo11 [35]

Answer:

SAA

Step-by-step explanation:

HOPE IT HELPS YOU IN YOUR LEARNING PROCESS.

4 0
2 years ago
Find the LCM of 10 and 15
jek_recluse [69]

Answer:

30

LCM of 10 and 15 is 30

Step-by-step explanation:

HOPE THIS HELPS YOU!!!!!!!! :D

7 0
2 years ago
Read 2 more answers
A circle is shown. 2 raddi are drawn. A chord connects the points of the radii on the circle to each other to form a triangle. T
iragen [17]

Answer:

(5\pi-11.6)ft^2

Step-by-step explanation:

Given:

Length of radius of circle = 5 feets

Length of perpendicular bisector = 4 feets

To find:

Area of the shaded portion of the circle

Solution:

As OD is perpendicular bisector of AB,

AB=2AD=2(2.9)=5.8\,\,feets

\angle ODA=90^{\circ}

Area of \Delta AOB = 1/2 (base) × (height) = \frac{1}{2}\times 4\times 5.8=11.6  square feets

Area of sector AOBC = \frac{\angle AOB}{360^{\circ}}\pi(r^2)=\frac{72^{\circ}}{360^{\circ}}\pi(5^2)=5\pi  square feets

Here, r denotes radius of circle

So,

Area of shaded portion = Area of sector AOBC - Area of \Delta AOB = (5\pi-11.6)ft^2  

Download pptx
3 0
3 years ago
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