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Lubov Fominskaja [6]
3 years ago
8

Write the equation of the line graphed below.

Mathematics
1 answer:
trapecia [35]3 years ago
6 0
<h2>y = -0.25x + 2</h2><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>
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I just need the straight up answer lolol
Licemer1 [7]
The correct answer is -5
8 0
3 years ago
How many different ways can teams of four members be formed from a class of 20?
guapka [62]
Assuming you want to choose 4 people from the class of 20; 

Begin by using the combinations formula; 

20C4=4845 possibilities 

Hope I helped :) 
4 0
3 years ago
What is the solution set of the equation?<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20-18%2B9x%3Dx" id="TexFormula1"
bagirrra123 [75]

9514 1404 393

Answer:

  x ∈ {2.07014981016}

Step-by-step explanation:

The equation can be rewritten as ...

  √x = 18-8x

  x = 324 -288x +64x²

  64x² -289x +324 = 0

  x = (289 ±√577)/128 ≈ {2.07015, 2.44548}

Since √x must be positive, we know that ...

  18 -8x ≥ 0

  x ≤ 18/8 = 2.25

The larger of the above solutions is extraneous, so the solution set is ...

  x ∈ {(289 -√577)/128} ≈ {2.07015}

8 0
2 years ago
Please help me
Bumek [7]

Answer:

10

Step-by-step explanation:

4 0
3 years ago
If the length of a rectangular garden is 2 feet less than the length of a house and the width of the garden is 5 feet less than
Goshia [24]

Answer:

A(h)  =  h²/2 - 6*h + 10

Step-by-step explanation:

The garden is rectangular, and area of a rectangle is:

A(r) = L*w

Where L is the length and w is the width of the rectangle

Now if we call "h" the length of the house, we have the following expressions

L = h - 2  and

w = h/2 - 5

The expression for the area f the ectangle as a function of the length of the house is:

A(h)  =  ( h - 2 )* ( h/2 -5 )

A(h)  = h²/2 - 5*h - h + 10

A(h)  =  h²/2 - 6*h + 10

3 0
3 years ago
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