No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.
Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have

and since the relation of order "<" is transitive, this implies

Answer:
<h2>

</h2>
Step-by-step explanation:
x - y² = -1 ⇒ - y² = - x - 1 ⇒ y² = x + 1 {x≥-1}
4x² + 9y² = 72
4x² + 9(x + 1)² = 72
4x² + 9(x² + 2x + 1) = 72
4x² + 9x² + 18x + 9 - 72 = 0
13x² + 18x - 63 = 0 ⇒ a = 13, b = 18, c = -63

Answer:
it is 5/6
Step-by-step explanation:
it's easy. There are 5 numbers that are greater than 2.
I think the answer is A. I hope this helps
Answer:
Hypotenuse length is (√2)x if the leg lengths are x and x respectively.
Step-by-step explanation:
This is an isosceles right triangle. The two acute angles are 45 degrees each and the leg lengths can be represented by x. Applying the Pythagorean Theorem, we get x^2 + x^2 = h^2 (where h is the length of the hypotenuse), or
2x^2 = h^2.
Solve this for h. Taking the square root of both sides of this equation, we get:
(√2)x = h
Conclusion: if the two legs of this equilateral right triangle are x and x, respectively, the length of the hypotenuse is h = √2x.