False I think, please don't quote me on that
Solution: We are given:
μ=3.1,σ=0.5,n=50
We have to find P(Mean <2.9)
We need to first find the z score
z= (xbar-μ)/(σ/sqrt(n))
=(2.9-3.1)/(0.5/sqrt(50))
=(-0.2)/0.0707
=-2.83
Now we have to find P(z<-2.83)
Using the standard normal table, we have:
P(z<-2.83)=0.0023
Therefore the probability of the sample mean being less the 2.9 inches is 0.0023
d1 = ax + by + c = 0 and d2= mx + ky + f = 0
if they are parallel :
8x + 2y = 7
8x + 2y - 7 = 0
- 8x + 2y -9 = 0
- 4x + y -6 = 0
- 16x + 4y - 19 = 0
you can create more whatever you want =)
Hope this helps ^-^
. What are the lower, middle, and upper quartiles of this data? 23, 15, 22, 15, 23, 15, 13, 21, 14 a. lower: 15, middle: 15, upp
icang [17]
The correct answer us D. lower: 14.5 middle: 15 upper: 22.5
Answer:
The fraction 1/3 is not equivalent to a a terminating decimal, the fraction is equivalent a number that does not terminate (repeating decimal)
Step-by-step explanation:
we know that
A <u>terminating decimal</u> it's a decimal with a finite number of digits.
A <u>repeating decimal </u>is a decimal that has a digit, or a block of digits, that repeat over and over and over again without ever ending
In this problem we have
1/3=0.33333333...
The digit 3 repeat over and over and over again without ever ending
therefore
The fraction 1/3 is not equivalent to a a terminating decimal, the fraction is equivalent a number that does not terminate (repeating decimal)
