Answer:
Uh...I think you forgot about the actaul question. But I'm gonna say Brady cause why not
Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3
Answer:
Therefore the latitude closest to the equator is 6.49°(approx).
Step-by-step explanation:
Given the path of a solar ellipse is modeled by
where f(t) is the latitude in degrees south of the equator at t minutes.
We know that ,
The minimum or maximum value of a function y(t) =at²+bt+c
is when
In this case a= 0.00223, b= - 0.558 and c= 41.395.
The minimum value of f(t)
when
=125.11
Therefore the latitude closest to the equator is
f(125.11)=0.00223(125.11)²-0.558×125.11+41.395
≈6.49
Hi!
Since you’ve been left with x’s on both sides of your equation, you would now want all of your x’s on one side. Since it would be easiest to get rid of the -3x on the right, you would add 3x on each side of the equation. This would result in your equation now being 10x=120. To get x on its own, you need to divide each side by 10, giving you x=12 as your final answer. Hope this helps!! :)
Answer:
Step-by-step explanation: