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3 years ago

The sum of two consecutive integers is 183. What is the smaller integer?

Mathematics

2 answers:

pentagon [3]3 years ago

8 0

Answer:

yes the answer is 91

Step-by-step explanation:

i took the test and i got that one correct

Natali5045456 [20]3 years ago

5 0

91

Explanation: Since the ones digit ends in a 3, that means the the ones digits of the two consecutive integers must be 1 and 2 or 6 and 7. However, you see 18 in the number 183. 9 + 9 = 18. When you add 6 and 7, you have to carry over one. However, when you add 1 and 2, you do not. Therefore, the two consecutive numbers are 91 and 92. 91 is the smaller integer, so that is the answer.

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Step-by-step explanation:

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3 years ago

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3 years ago

Can you find the probability to each of these answers...

goldfiish [28.3K]

Problem 1

<h3>Answer: 7/10</h3>

-----------------------

Explanation:

The formula we'll use is

P(A or B) = P(A) + P(B)

which only works if A and B are mutually exclusive events.

P(A or B) = P(A) + P(B)

P(A or B) = 7/20 + 7/20

P(A or B) = (7+7)/20

P(A or B) = 14/20

P(A or B) = (7*2)/(10*2)

P(A or B) = 7/10

=========================================================

Problem 2

<h3>Answer: 3/4</h3>

-----------------------

Explanation:

We'll use the same formula as the previous problem.

P(A or B) = P(A) + P(B)

P(A or B) = 3/10 + 9/20

P(A or B) = 6/20 + 9/20

P(A or B) = (6+9)/20

P(A or B) = 15/20

P(A or B) = (3*5)/(4*5)

P(A or B) = 3/4

=========================================================

Problem 3

<h3>Answer: 3/5</h3>

-----------------------

Explanation:

We'll use the same formula as the previous problem.

P(A or B) = P(A) + P(B)

P(A or B) = 7/20 + 1/4

P(A or B) = 7/20 + 5/20

P(A or B) = (7+5)/20

P(A or B) = 12/20

P(A or B) = (4*3)/(4*5)

P(A or B) = 3/5

=========================================================

Problem 4

<h3>Answer: 0</h3>

-----------------------

Explanation:

This time we're asked to find P(A and B), but since the two events are mutually exclusive, this means the probability of both occurring is 0.

Mutually exclusive events cannot happen simultaneously.

An example would be flipping heads and tails at the same time on the same coin.

The info about P(A) and P(B) is not relevant.

7 0

4 years ago

Fractions pt 2 cause lazy

Arada [10]

1/2 + 9/20 = 19/20
1/20 + 1/10 = 3/20
1/8 + 11/16 = 13/16
2/9 + 5/9 = 7/9
3/20 + 3/4 = 18/20 = 9/10
7/17 + 1/17 = 8/17

6 0

3 years ago

Read 2 more answers

Help help help me now

Anika [276]

The number of square meters of paint needed to cover the surface is 149.90m²

<h3>Surface area of composite solid </h3>

From the question, we are to determine the number of square meters of paint needed to cover the surfaces

The number of square meters of paint needed to cover the surfaces is equal to the surface area of the solid

Now, we will calculate the surface area of the composite solid

Surface area of the composite solid = $\pi r^{2} + 2\pi rh_{c} + 2(lh + wh) + lw-\pi r^{2}$

Where r is the radius of the cylindrical top

$h_{c}$ is the height of the cylindrical top

$l$ is the length of the box

$h$ is the height of the box

$w$ is the width of the box

From the given information,

r = 2 m

$h_{c}$ = 3 m

$l$ = 9 m

$h$ = 2.4 m

$w$ = 5 m

Putting the parameters into the equation, we get

Surface area of the composite solid = $(\pi \times 2^{2} )+ (2\pi \times 2 \times 3) + 2(9\times2.4 + 5\times2.4) + 9\times5-(\pi \times 2^{2} )$

= $(12\pi ) + 2(21.6 + 12) + 45$

= $12\pi + 2(33.6 ) + 45$

= $12\pi +67.2+ 45$

$= 12\pi +112.2$

$= 37.699 +112.2$

$= 149.8991$ m²

∴ Surface area of the composite solid ≅ 149.90m²

Hence, the number of square meters of paint needed to cover the surface is 149.90m²

Learn more on Calculating surface area of composite solid here: brainly.com/question/13175744

#SPJ1

3 0

3 years ago