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rusak2 [61]
3 years ago
10

SOLVING EACH SYSTEM BY ELIMINATION x+3y=5 x=-6y+14 HELP

Mathematics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

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an ice cream shop manager lowered the price for a single scoop of ice cream from 2.50 to 2.00 what is the precent of decrease in
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2 years ago
Power (denoted by PPP) can be defined as a function of work (denoted by WWW) and time (denoted by ttt) using this formula: P=\df
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Answer:

\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}

Step-by-step explanation:

Power (denoted by P) can be defined as a function of work (denoted by W) and time (denoted by t) using this formula:

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Unit of Work = \dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^2}

Unit for Time = s

Therefore, the Unit of Power

=$Unit for W \times \dfrac{1}{\text{Unit for time}}

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An appropriate unit for power is: \dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}

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3 years ago
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