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3 years ago

Question

SAT

1 answer:

Ghella [55]3 years ago

3 0

Answer:

0.456

0.324

Explanation:

The null and alternative hypothesis :

H0 : p = 0.40; HA :p < 0.40

Test statistic :

(Ph - P) / sqrt[(p*(1-p))/n]

Ph = X / n

X = 34 ; n = sample size = 80

Ph = 34 / 80 = 0.425

(0.425 - 0.4) / sqrt[(0.4(0.6)) / 80]

0.025 / sqrt(0.003)

0.025 / 0.0547722

Test statistic = 0.4564359

Test statistic = 0.456

Using the P-value from Zscore calculator :

Significance level of 95% ; one tailed

Z statistic value = 0.456

P value = 0.324195

= 0.324 ( 3 decimal places)

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