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BigorU [14]
3 years ago
14

Why are there problems with patching electronics such as heart rate monitors and MRI machines that run embedded Windows OSs?

Computers and Technology
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

The various problems with patching electronics such as heart rate monitors and MRI machines that run embedded Windows OSs is that they have a certification which is usually at a specific revision level.

Another issue is that probably the maker or the manufacturer didn’t provide the patch method which would have been used to fix such electronics.

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One lap around a standard high-school running track is exactly 0.25 miles. Write a program that takes a number of miles as input
salantis [7]

Answer:

import java.util.Scanner;

public class Miles {

public static void main(String[] args) {

   //initialization

       double Number_Miles;

       //print the message

       System.out.print("Enter the number of miles: ");

       Scanner scn1 = new Scanner(System.in);

       

       Number_Miles = scn1.nextDouble();  //read the input from user

       //calculate the laps

       double yourValue = Number_Miles/0.25;

       //display the output on the screen

       System.out.printf("%.2f", yourValue);

     

}

}  

Explanation:

First import the library Scanner than create the class and define the main function. In the main function, declare the variables.

print the message on the screen and then store the value enter by the user into the variable.

Scanner is a class that is used for reading the output. So, we make the object of the class Scanner and then object call the function nextDouble() which reads the input and store in the variable.

After that, calculate the number of laps by dividing the number of miles with the given one lap running track value (0.25 miles).

Number\,of\,laps = \frac{Number\,of\,miles}{0.25}

the output is stored in the variable.

After that, print the value on the screen with 2 digits after the decimal point.

we can use "%.2f" in the printing function in java.

like System.out.printf("%.2f", output);

5 0
3 years ago
Read 2 more answers
Briefly describe the working of computer processing system?
liberstina [14]

Answer:

<em>The Processor</em>

<em>The central processing unit (CPU) guides the computer through the various steps of solving a problem. Data enters the computer through an input unit, is processed by the central processing unit, and is then made available to the user through an output unit.</em>

<em>ExplanationExplanationExplanation:</em>

<em />

5 0
2 years ago
#Create a class called Name. Name should have two attributes
prisoha [69]

Answer:

//class Name

class Name {

// attributes gave you 3

String first_name;

String last_name;

int length = 0;

//constructor with 2 parameters

Name(String first_name, String last_name){

}

//methods

public String find_printed_name(){

return first_name + " " + last_name;

}

public void find_sortable_name(){

return last_name + ", " first_name.charAt(0);

}

public static void main(String[] args){

// instantiate the class

Name test_name = new Name("David", "Joyner");

System.out.println(test_name.first_name);

System.out.println(test_name.last_name);

System.out.println(test_name.find_printed_name());

System.out.println(test_name.find_sortable_name());

}

Explanation:

You didn't specify a language so I did it in Java.

You should know how to declare methods in Python.

3 0
3 years ago
A user needs to use her laptop to give a presentation using a video projector. she called asking you how to switch the display t
Doss [256]

<span>I would advise her to press the fn keyboard key along with the function key with a monitor connected on it. She should ensure that she has the correct cable to connect the laptop to the projector. Most laptops require a manual switch by pressing these combination keys but for some, they will automatically detect the external display and switch to video output</span>

 

4 0
3 years ago
What is the maximum number of edges for an undirected graph? A directed graph?
siniylev [52]

Answer:

For undirected graph n(n-1) for directed graph \frac{n(n-1)}{2}

Explanation:

The maximum number of edges for a undirected graph is given by n(n-1), where n is number of vertices

The maximum number of edges in directed graph is given by \frac{n(n-1)}{2}, where n is number of vertices

The maximum number of edges is greater in undirected graph than directed graph

5 0
4 years ago
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