The solutions for the given system of equations are:
(3, 0), (-4, 7).
<h3>
How to solve the given system of equations:</h3>
Here we have the system:
x + y = 3
y = x² - 9
To solve this, we can replace the second equation into the first one, so we get:
x + (x² - 9) = 3
Now we can solve this quadratic equation for x, we need to solve:
x² + x - 12 = 0.
The solutions are given by Bhaskara's formula:
Then the two solutions are:
x = (-1 + 7)/2 = 3
x = (-1 - 7)/2 = -4
To get the y-values correspondent, we can evaluate the linear equation in these two values:
y = 3 - x.
For x = 3:
y = 3 - 3 = 0
For x = -4:
y = 3 + 4 = 7
Then the two solutions are: (3, 0), (-4, 7).
If you want to learn more about systems of equations:
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1/3, because the probability in the cube is 1/6, and there are 2 numbers less than 3. So, 2/6 and simplify 2/6 to 1/3.
Answer:
Tammy has sold 40 boxes so far
Step-by-step explanation:
Hello! :)
Answer:
Let the smallest digit, or the units' digit, be equal to x:
Tens' digit is four more, therefore:
x + 4 represents the tens' digit.
Hundreds' digit is 2 more than the tens' digit, so:
2 + (x + 4), or x + 6 represents the hundred's digit.
These all sum up to 13, so write an expression to represent this:
x + (x + 4) + (x + 6) = 13
Combine like terms:
3x + 10 = 13
Subtract 10 from both sides:
3x = 3
Divide both sides by 3:
x = 1
Find the digits using the rules listed above:
Hundreds' digit: (1) + 6 = 7
Tenths' digit: (1) + 4 = 5
Units' digit: 1 = 1
Therefore, the number is:
751.
