Answer: Anything between 0 and 10, excluding both endpoints.
In terms of symbols we can say 0 < w < 10 where w is the width.
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Explanation:
You could do this with two variables, but I think it's easier to instead use one variable only. This is because the length is dependent on what you pick for the width.
w = width
2w = twice the width
2w-5 = five less than twice the width = length
So,
which lead to
area = length*width
area = (2w-5)*w
area = 2w^2-5w
area < 150
2w^2 - 5w < 150
2w^2 - 5w - 150 < 0
To solve this inequality, we will solve the equation 2w^2-5w-150 = 0
Use the quadratic formula. Plug in a = 2, b = -5, c = -150
![w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-150)}}{2(2)}\\\\w = \frac{5\pm\sqrt{1225}}{4}\\\\w = \frac{5\pm35}{4}\\\\w = \frac{5+35}{4} \ \text{ or } \ w = \frac{5-35}{4}\\\\w = \frac{40}{4} \ \text{ or } \ w = \frac{-30}{4}\\\\w = 10 \ \text{ or } \ w = -7.5\\\\](https://tex.z-dn.net/?f=w%20%3D%20%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D%5C%5C%5C%5Cw%20%3D%20%5Cfrac%7B-%28-5%29%5Cpm%5Csqrt%7B%28-5%29%5E2-4%282%29%28-150%29%7D%7D%7B2%282%29%7D%5C%5C%5C%5Cw%20%3D%20%5Cfrac%7B5%5Cpm%5Csqrt%7B1225%7D%7D%7B4%7D%5C%5C%5C%5Cw%20%3D%20%5Cfrac%7B5%5Cpm35%7D%7B4%7D%5C%5C%5C%5Cw%20%3D%20%5Cfrac%7B5%2B35%7D%7B4%7D%20%5C%20%5Ctext%7B%20or%20%7D%20%5C%20w%20%3D%20%5Cfrac%7B5-35%7D%7B4%7D%5C%5C%5C%5Cw%20%3D%20%5Cfrac%7B40%7D%7B4%7D%20%5C%20%5Ctext%7B%20or%20%7D%20%5C%20w%20%3D%20%5Cfrac%7B-30%7D%7B4%7D%5C%5C%5C%5Cw%20%3D%2010%20%5C%20%5Ctext%7B%20or%20%7D%20%5C%20w%20%3D%20-7.5%5C%5C%5C%5C)
Ignore the negative solution as it makes no sense to have a negative width.
The only practical root is w = 10.
If w = 10 feet, then the area = 2w^2-5w results in 150 square feet.
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Based on that root, we need to try a sample value that is to the left of it.
Let's say we try w = 5.
2w^2 - 5w < 150
2*5^2 - 5*5 < 150
25 < 150 ... which is true
This shows that if 0 < w < 10, then 2w^2-5w < 150 is true.
Now try something to the right of 10. I'll pick w = 15
2w^2 - 5w < 150
2*15^2 - 5*15 < 150
375 < 150 ... which is false
It means w > 10 leads to 2w^2-5w < 150 being false.
Therefore w > 10 isn't allowed if we want 2w^2-5w < 150 to be true.