For this case we have the following polynomials:
3x2
x2y + 3xy2 + 1
We have then:
For 3x2:
Classification: polynomial of one variable:
Degree: 2
For x2y + 3xy2 + 1:
Classification: polynomial of two variables
Degree: 2 + 1 = 3
Answer:
The polynomial 3x2 is of one variable with a degree of 2.
The polynomial x2y + 3xy2 + 1 is of two variables a with a degree of 3.
Answer:
if you are looking for the area this are the answers
Step-by-step explanation:
4: 
how: .5 x 25 x 10 = 125
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5: 
how: .5 x 16 x 13 = 104
remember to put the ".5" when you are multiplying
I hope this help you
have a good night :)
Answer:
A
Step-by-step explanation:
Answer:
∠ 1,3,5,7 = 32°
∠2,4,6,8,= 148°
Step-by-step explanation:
From the figure attached,
AB and CD are two parallel lines and another transverse line is intersecting these line at two distinct points.
Since, m∠1 = 32°,
∠1 and ∠4 are supplementary angles [Linear pair of angles]
m∠1 + m∠4 = 180°
32° + m∠4 = 180°
m∠4 = 180° - 32°
m∠4 = 148°
therefore,
m∠1,3,5,7 = 32°
m∠2,4,6,8,= 148°
