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sashaice [31]
3 years ago
14

(x^-6)^4 Someone please help me :)

Mathematics
1 answer:
Anastasy [175]3 years ago
3 0
The answer I came up with was ×^6-4. Just rewrite it. I hope this was helpful.
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Among 6 electrical components exactly one is known not to function properly. If 2 components are randomly selected, find the pro
Oksanka [162]

Answer:

66.67% probability that all selected components function properly

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the components are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Desired outcomes:

2 components which function properly, from a set of 5. So

D = C_{5,2} = \frac{5!}{2!(5-2)!} = 10

Total outcomes:

2 components, from a set of 6. So

T = C_{6,2} = \frac{6!}{2!(6-2)!} = 15

Probability:

p = \frac{D}{T} = \frac{10}{15} = 0.6667

66.67% probability that all selected components function properly

3 0
3 years ago
Solve for xxx. Write the smaller solution first, and the larger solution second.
____ [38]

Answer:

x=-5\text{ or }x=2

Step-by-step explanation:

We have been given an equation x^2+3x-10=0. We are asked to find the solutions of our given equation.

We will use splitting the middle term method to solve quadratic equation.

We will split middle term of our given equation into parts such that whose product is -10 and whose sum is 3.

We know that such two numbers are 5\text{ and }-2.

x^2+5x-2x-10=0

(x^2+5x)+(-2x-10)=0

x(x+5)-2(x+5)=0

(x+5)(x-2)=0

Using zero product property, we will get:

(x+5)=0\text{ or }(x-2)=0

x+5=0\text{ or }x-2=0

x=-5\text{ or }x=2

Therefore, the solutions for our given equation are x=-5\text{ or }x=2.

4 0
3 years ago
Read 2 more answers
Can someone help me with this please
stellarik [79]

Ok so we'll  go ahead and solve for y first -  we just need to get it alone on one side of the equal sign

Step 1: subtract 2x from each side

2x - 7y - 2x = 19 - 2x

This cancels out the 2x on the left, giving us

-7y = 19 - 2x

Step 2: divide both sides by -7

\frac{-7y}{-7} = \frac{19}{-7} + \frac{-2x}{-7}

This gives us

y = -19/7 + 2x/7

That should be your answer for the first question. Now solving the next parts are easy. All you need to do is plug in x.

When x = -3

y = -19/7 + 2x/7

y = -19/7 + 2(-3)/7

y = -19/7 - 6/7

y = -25/7


When x = 0

y = -19/7 + 2x/7

y = -19/7 + 2(0)/7

y = -19/7


When x = 3

y = -19/7 + 2x/7

y = -19/7 + 2(3)/7

y = -19/7 + 6/7

y = -13/7


Hope that helps! Feel free to ask if I can help with anything else :)

7 0
2 years ago
Lim->infinity 4n^2/n^2+10000n
dybincka [34]
<span>let P(n)=4n² /  n²+10000n
when n ----------> infinity, the main rule is as follow
lim </span><span>P(n)=4n² /  n²+10000n = lim </span>P(n)=4n² /  n²= lim 4=  4
n ----------> infinity  <span>                n ----------> infinity  </span><span>n ----------> infinity
finally
</span>
<span>Lim->infinity 4n^2/n^2+10000n = 4</span>
4 0
3 years ago
In 15–20, write the number positioned at each point.
Mumz [18]

Answer:

See below.

Step-by-step explanation:

15.) -3.25

16.) -4.5

17.) 1.25

18.) -5.75

19.) 0.5

20.) -2.5

5 0
3 years ago
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