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pentagon [3]
3 years ago
8

POS

Mathematics
1 answer:
meriva3 years ago
7 0

Answer:

0.08 = 8%

2.3= 230%

0.34= 34%

1.05= 105%

0.7= 70%

0.049= 4.9%

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nikklg [1K]
All you need to do is divide 161 by 7 and get 23 weeks

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176.59 in word form​
lorasvet [3.4K]

Answer:

one hundred seventy-six and fifty-nine hundredths

Step-by-step explanation:

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Graph the line whose y-intercept is -7 and whose x-intercept is 1
vesna_86 [32]

Answer:

y=7x -7

Step-by-step explanation:

We are given two points, the y - intercept and the x - intercept.

The y - intercept being: ( 0, -7 )

The x - intercept being: ( 1, 0 )

The equation of a line in slope - intercept form is:

y = mx + b, where m is the slope and b is the y - intercept.

We already have the y - intercept. So far we have:

y = mx - 7

What we're missing is the slope.

To find the slope, we can use this formula:

\frac{y_{2}-y_{1}  }{x_{2}-x_{1}}, where x_{2} and x_{1} are the x - coordinates of both points and y_{2} and x_{1} are the y - coordinates of both points.

m=\frac{0-(-7)}{1-0} \\\\m=\frac{7}{1}\\m=7

We now have the missing piece, the slope, so the equation now is:

y=7x -7

3 0
3 years ago
The height of a trapezoid is 15m and the midsegment is 32m. What is the area of the trapezoid?
viktelen [127]
The formula is: A=1/2 h (base one + base two) 

<span>Plug in your numbers and you will get the area.</span>
6 0
3 years ago
What are the potential solutions of In(x^2-25)=0?
Maslowich

Answer:

x =\pm \sqrt{26}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>

\implies log_e {(x^2-25)}= 0

<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>

  • If we have a logarithmic equation as ,

\implies log_a b = c

Then this can be written as ,

\implies a^c = b

In a similar way we can write the given equation as ,

\implies e^0 = x^2 - 25

  • Now also we know that a^0 = 1 Therefore , the equation becomes ,

\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}

<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>

6 0
3 years ago
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