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just olya [345]
3 years ago
10

What is the greatest common factor of 12 and 18? A. 2 B. 6 C. 4 D. 12

Mathematics
2 answers:
S_A_V [24]3 years ago
4 0

Answer:

B. 6

Step-by-step explanation:

D. 12 cant be multiplied to get 18

C. 4 cant be multiplied to get 18

A. 2 is a common factor of 12 and 18 but not the greatest.

B. 6 times 2 is 12 and 6 times 3 is 18 so 6 is the greatest common factor.

ella [17]3 years ago
3 0

Answer:

B

Step-by-step explanation:

Factors of 12: 1, 2, 3, 4, 6, 12

Factors of 18: 1, 2, 3, 6, 9, 18

The common ones are 1, 2, 3, and 6. The greatest one among these is 6.

Factors are numbers you multiply with another natural number to get another number. For example, the factors of 16 will be all the numbers that can be multiplied with an integer to get 16. 1* 16 is 16, so 1 will work. 2 *8 is 16, so 2 will work. But, 3 * 16/3 is 16 so 3 won't work. You get the point. Hope this helps and pls give brainliset.

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In the problem, 2x4 - 3x3 - 6x2 + 11x +8 divided by (x - 2), what is the remainder?
Jet001 [13]

remainder = 14

2x^{4} - 3x^{3} - 6x² + 11x + 8

= 2x³ + x² - 4x + 3 + \frac{14}{x - 2}


8 0
4 years ago
1.Give one number that makes the inequality x + 7 > 20 true
nata0808 [166]
1. Any number above 13 works. Why? Because 20-7=13, and to be greater than 20, you must add a number larger than 13.

Examples: 14+7 > 20, 30+7 > 20, 100+7 > 20

2. Any number below 25/3 (which is also 8.3 with a repeating 3) works. Why? Because 25/3=8.3 with a repeating 3, and to remain less than 25, you must multiply by a number less than 8.3 with a repeating 3.

Examples: 3(8) < 25, 3(5) < 25, 3(0) < 25

3. 4 buses. 1 bus will hold 60 students, 2 will hold 120, 3 will hold 180, and 4 will hold 240. The question is trying to trick you into putting now 3.3333333333... buses because that's what 200/60 is, but there is no such thing as a third of a bus. So you need at least 4 buses. (There will be an extra 40 spaces for passengers on the 4th bus, but that is okay.)

To find this answer I did 200/60 and got 3.3 with a repeating 3. You must round to the higher whole number. Rounding down to 3 buses leaves you with 20 students without a bus.

4. 19 boxes. 18 boxes will only hold 288 candies. The question is trying to trick you into putting down 18.75 boxes because that's what 300/16 is, but there is no such thing as 75% of a box. So you need at least 19 boxes. (There will be an extra 4 spaces for candies in the 19th box, but that is okay.)

To find this answer I did 300/16 and got 18.75. You must round to the higher whole <span>number. Rounding down to 18 boxes leaves you with 12 candies without a box.</span>
6 0
3 years ago
How many five digit numbers can be formed from the digits 1,,3,4,5,6,7 if no digit is repeated
Viktor [21]

<em>To get all possible permutations of these five spaces, we just multiply these numbers (that is, 8∗7∗6∗5∗4=6,720)</em>

<em>There are 6,720 five digit numbers that can be formed from the digits provided given that no digit may be repeated.</em>

<em>Hope that helped!</em>

3 0
3 years ago
Read 2 more answers
Does anybody know this ?
Aleonysh [2.5K]

Answer:

0, 1, 2, 3, 4

Step-by-step explanation:

Multiply each x value by 1/3 then add 2. Since the numerator is 1, you would multipy by one and divide by the denominator of 3, so you really need to divide each x value by 3 then add 2.

-6:

-6/3 = -2

-2 + 2 = 0

-3:

-3/3 = -1

-1 + 2 = 1

0:

0/3 = 0

0 + 2 = 2

3:

3/3 = 1

1 +2 = 3

6:

6/3 = 2

2 + 2 =4

5 0
2 years ago
Write a system of linear inequalities represented by the graph.<br> Inequality 1:<br> Inequality 2:
Keith_Richards [23]

Answer:

Inequality (1) → y > 2x

inequality (2) → x ≥ -2

Step-by-step explanation:

If the inequality (1) is a dotted line passing through origin.

Since, shaded area is above the dotted line,

Equation of the inequality will be in the form of y > mx +b

Here m = slope of the dotted line

b = y-intercept

Since, this line is passing through the origin,

Therefore, y-intercept = 0

Slope 'm' of the line = \frac{\text{Rise}}{\text{Run}}

                                 = \frac{2}{1}

                             m = 2

Inequality (1) → y > 2x

Second inequality is represented by the shaded area on the right side of  the dark vertical line, x = -2,

Therefore, inequality 2 will be → x ≥ -2

4 0
3 years ago
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