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2 years ago

Plz help and I will give brainliest

Mathematics

1 answer:

kirill [66]2 years ago

4 0

Answer:

6 True False True False

7 41.979

Step-by-step explanation:

6. 24 and 18. 24 is 2*2*2*3 and 18 is 3*3*2

Common is 6.

so a is correct.

B is wrong because they have to be the same

C is correct.

D is wrong because 48 does not go into 18 easily.

12.329+10.45+19.2

41.979

Hope this helps :D

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The answer is 1 :)

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3 years ago

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2 years ago

Please please help me with this

swat32

N=1→an=a1 (first term)=16 (on the graph for n=1)→First term = 16
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Simplifying the fraction dividing the numerator (4) by 4 and the denominator (16) by 4:
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2 years ago

Evaluate the following integral using trigonometric substitution

serg [7]

Answer:

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

Step-by-step explanation:

We are given the following integral:

$\int \frac{dx}{\sqrt{9-x^2}}$

Trigonometric substitution:

We have the term in the following format: $a^2 - x^2$ , in which a = 3.

In this case, the substitution is given by:

$x = a\sin{\theta}$

$dx = a\cos{\theta}d\theta$

In this question:

$a = 3$

$x = 3\sin{\theta}$

$dx = 3\cos{\theta}d\theta$

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}$

We have the following trigonometric identity:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

$1 - \sin^{2}{\theta} = \cos^{2}{\theta}$

Replacing into the integral:

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C$