C. best represents the equation
Answer:
Option D. 9
Step-by-step explanation:
There are two ways to obtain the answer to the question.
Method 1:
Let 2x + 1 = 0
Making x the subject, we have
2x + 1 = 0
Collect like terms
2x = –1
Divide both side by 2
x = –1/2
Now, put the value of x into the expression 4x³ – 6x² – 8x + 7, we have:
4x³ – 6x² – 8x + 7
x = –1/2
4(–1/2)³ – 6(–1/2)² – 8(–1/2) + 7
4(–1/8) – 6(1/4) – 8(–1/2) + 7
–1/2 – 3/2 + 4 +7
– 4/2 + 4 + 7
– 2 + 4 + 7
= 9
Method 2:
Divide 4x³ – 6x² – 8x + 7 by 2x + 1
Please see attached photo for explanation.
okay. the point has an x and y value. place them into the equation.
1=m(1)+b
m=slope, and theequation tells you that slope is 7.
1=7(1)+b
now you need to figure out what b is.
1=7(1)+b
^
1= 7 +b
-7 -7
---------------
-6=B
b is 6. now place it into the equation, replacing the x and y values back.
y=7x-6.
write 7 and 6 in the boxes (the negative for the six has already been provided)
Answer:
T = 47.1875°C
Step-by-step explanation:
Given:
Surrounding temp, Ts = 100°C
Initial Temperature ,T0= 20°C
Increase in temperature = 15°C
Final temperature, T = 20 + 15 = 35°C
Time, t = 9 seconds
Let's take Newton's law of cooling:

We'll solve for k

Divide both sides by -5


Let's now find the temperature of the ball after 18 seconds in boiling water.
Use the Newton's equation again:




T = 47.1875°C
Temperature of the ball after 18 seconds in boiling water is 47.1875°C
Step-by-step explanation:

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{\frac{1}{7}} = 0 \\ Period → \frac{2}{1}π = 2π](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B0%7D%7B%5Cfrac%7B1%7D%7B7%7D%7D%20%3D%200%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7B1%7D%CF%80%20%3D%202%CF%80)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is.
I am joyous to assist you anytime.