Is angle B a right angle ?

The line graph shows the number of goals scored

Neporo4naja [7]

Answer:

a) 1 game

b) 41 goals

c) median = 2

Step-by-step explanation:

a)

As we can see in the line graph, where we have the 0 for the number of goals scored, the graph indicates only 1 in the number of games, so we have only 1 game where no goals were scored.

b)

To find the total number of goals scored, we multiply the goals scored by the number of games for that score, and then sum them all:

total goals = 1*0 + 4*1 + 5*2 + 6*3 + 1*4 + 1*5 = 41 goals

c)

To find the median, we put all the goals in crescent order, and then find the value in the middle. As we have 18 games, the middle value will be an average of the 9th and 10th terms.

We have 1 number 0, 4 numbers 1 and 5 numbers 2 in the beginning, so for these 10 numbers, the 9th and the 10th are the score 2, so the median is 2.

8 0

3 years ago

Find the distance between points P(9,8) and Q(7,6) to the nearest tenth.

sergey [27]

Answer:

2.8 units

Step-by-step explanation:

Think of this distance as the hypotenuse of a right triangle that has a vertical leg and a horizontal one as well.

Going from P to Q, the change in x is 2 and the change in y is also 2.

Thus, by the Pythagorean Theorem, this desired distance is:

d = √(2^2 + 2^2) = 2√2 units, or 2.8 units

6 0

3 years ago

A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s

quester [9]

Answer:

a) $P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

b) $p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

c) $L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

d) $L_q =\frac{20^2}{30(30-20)}=1.333 people$

e) $W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

f) $W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

$p_x$ represent the probability that the employee is busy

$L_s$ represent the average number of people receiving and waiting to receive some information

$L_q$ represent the average number of people waiting in line to get some information

$W_s$ represent the average time a person seeking information spends in the system

$W_q$ represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

$\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}$

And in order to find the probability we can do this:

$P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

Part b

Find the proportion of the time that the employee is busy

This proportion is given by:

$p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

Part c

Find the average number of people receiving and waiting to receive some information

In order to find this average we can use this formula:

$L_s= \frac{\lambda}{\lambda -\mu}$

And replacing we got:

$L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

Part d

Find the average number of people waiting in line to get some information.

For the number of people wiating we can us ethe following formula"

$L_q =\frac{\lambda^2}{\mu(\mu-\lambda)}$

And replacing we got this:

$L_q =\frac{20^2}{30(30-20)}=1.333 people$

Part e

Find the average time a person seeking information spends in the system

For this average we can use the following formula:

$W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

Part f

Find the expected time a person spends just waiting in line to have a question answered (time in the queue).

For this case the waiting time to answer a question we can use this formula:

$W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

6 0

3 years ago

Read 2 more answers

Mark charges 100.00 for an encoding work. In addition, he charges 5.00 per page of printed output.

o-na [289]

The total amount charged for each work can be expressed by the equation : 100 + 5x

Fixed charged per work = 100.00

Charge per page printed = 5.00

<u>Let the number pages printed be represented as x :</u>

Total amount charged for n pages can be related thus :

Fixed charge per work + (cost per page × number of pages)

100 + 5x

Therefore, the total amount charged can be expressed with the equation 100 + 5x

Learn more :brainly.com/question/18796573

7 0

2 years ago

If a² + b² = z and ab = y, which of the following is equivalent to 4z + 8y? Show all the steps.

Ivenika [448]

Answer:

The answer to your question is: (2a + 2b)²

Step-by-step explanation:

a² + b² = z

ab = y

Which is equivalent to 4z + 8y ?

Substitution

4(a² + b²) + 8(ab)

Simplify 4a² + 4b² + 8ab

Order 4a² + 8ab + 4b² It's a perfect square trynomial

Factorize (2a + 2b)²

7 0

4 years ago

Read 2 more answers