If the length of AB is 10 cm from the center and has a length of 12, find the approximate length from the center to CD.
1 answer:
<u>Given</u>–
AB = 12 Cm
CD = 14 Cm
PO = 10 Cm
AP = 1/2 × 12 = 6 Cm
<u>Construction</u>–
Draw NO such that it is the perpendicular bisector of CB.
Hence,
ND = 1/2 × 14 = 7 Cm
To Find,
Measure of NO
<u>Solution</u>,
Here, PO Perpendicular to AB
Hence, APO is a right-angled triangle–
AO² = PO² + AP²
Or, AO² = 10 ² + 6 ²
Or, AO² = 36 + 100
Or, AO = √136 Cm
Or, AO = 11.66 Cm
Also, AO = OD = 11.66 Cm
( Radius of the same circle )
Now, in triangle OND,
OD² = ON² + ND ²
Or, 11.66 ² = ON² + 7²
Or, 136 = ON² + 49
Or, ON ² = 136 – 49
Or, ON ² = 87
Or, ON ² = √87
Or, ON = 9.3 Cm
Therefore, the appropriate length from center to CD is 9.3 Cm.
You might be interested in
.63, 69%, 0.72, 3/4, there you gooooo
Answer:
I think that the answer is
b = 7
Here is the step-by-step solution.....
See the attached files for the step-by-step solution...><><
Answer: Electrons in water act in a similar way to visible light so they don't absorb or reflect most of the light. Instead they allow it to pass through relatively unimpeded, absorbing wavelengths like infrared and reflecting invisible UV
Answer:
boxes, 3,4,7,9,10,11 and 13 are the ones to be shaded.
hope this helps (: