Evaluate the following limit Lim x approaching 2 (x^2)-1/x-2
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Answer:
see explanation
Step-by-step explanation:
The y- intercept is at (0, 6) ⇒ c = 6
The x- coordinate of the vertex is at the midpoint of the zeros, that is
m = =
= - 2
Since the zeros are x = - 3 and x = - 1 then the factors are (x + 3), (x + 1) and
f(x) = a(x + 3)(x + 1) = a(x² + 4x + 3)
Comparing with f(x) = ax² + 8x + 6 ⇒ a = 2
Thus
f(x) = 2x² + 8x + 6
Substitute m = - 2 into the equation for value of n
n = 2(- 2)² + 8(- 2) + 6 = 8 - 16 + 6 = - 2
Hence
c = 6, m = - 2, a = 2, n = - 2