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trapecia [35]
2 years ago
5

What is the the distance between a point at (-3,4) and a point at (2,-5)

Mathematics
1 answer:
zaharov [31]2 years ago
4 0
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

What is the distance between a point at (-3,4) and a point at (2,-5) ?

<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

Let the two points be A and B .

And, let the distance be P .

Now, the distance P between the point A (-3,4) and the point B (2,-5) is

\bf P \: = \sqrt{(-3 \: - \: 2)^2 \: + \: (4 \: + \: 5)^2}

\implies \bf P \: = \sqrt{(-5)^2 \: + \: (9)^2}

\implies \bf P \: = \sqrt{25 \: + \: 81}

\implies \bf P \: = \sqrt{106}

\implies \bf P \: = \: 10.3

<h3>The distance between a point at (-3,4) and a point at (2,-5) is <u>1</u><u>0</u><u>.</u><u>3</u> . [Answer]</h3>
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Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit
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Changing the equation into slope form: y = mx + c, where m is the slope [gradient] and c is the y-intercept.

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Graphing y=- \frac{2}{3}x+490 using slope-intercept method:
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-----------------------------------------------------------------------------------------------------------

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Rewriting this into slope-equation form

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-------------------------------------------------------------------------------------------------------------

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