Ask question

Ask question

All categories

3 years ago

10

Extremely Easy Math!!! 50 Points!!! BRAINLIEST!!!

1 answer:

N76 [4]3 years ago

4 0

Answer:

x = 40

Step-by-step explanation:

If you add the total of 3 angles in a STRAIGHT line, you have to get 180 in total.

So, x = 180 - ( 80 + 60 )

= 180 - 140

= 40

You might be interested in

If joan reads 96 pages in 4 hours how long will it take her to read 240

vfiekz [6]

Answer:

10 hours to readm240

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

James pays $120.00 for golf clubs that are on sale for 20% off at Golf Pros.At Nine Iron, the same clubs cost$8.00 less than the

Oxana [17]

Answer:

17b

Step-by-step explanation:

8980

80987

78987=

6 0

3 years ago

Explain part a and b

xxTIMURxx [149]

As i can see there is a table a bove so the x is the first number which going up the graph and the y is across the line

6 0

3 years ago

(q^4)^z= q^12 find the value of z

juin [17]

Answer:

z = 3

Step-by-step explanation:

we use the method

(x^a)^b = x^(a*b)

so

(q^4)^z = q^(4*z)

now

4*z = 12

z = 12 / 4

so

z = 3

4 0

3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago