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lord [1]
2 years ago
9

What is the value of the expression below? −5+∣9−11∣

Mathematics
2 answers:
tia_tia [17]2 years ago
6 0
You MUST perform the operation 9-11 first, since it's between the vertical "absolute value" lines:  |9-11].     Thus, |9-11] comes out as |-2|, which is equal to 2 ("the absolute value of -2 is positive 2").

Thus, -5 + |9-11|  =  -5 + 2  = -3 (answer)
Helen [10]2 years ago
4 0
-5+|9-11|
first, you would find the absolute value
|9-11|= |-2|=2
then the problem looks like this
-5+2= -3
So, the answer is negative three
 
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WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but x \ne 0</h3>

To write this in interval notation, we can say (-\infty, 0) \cup (0, \infty) which is the result of poking a hole at 0 on the real number line.

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The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say (-\infty, \infty) which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

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Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

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Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

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Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

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Part (e)

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