The sum of the first n natural numbers and 0=
n*(n+1)/2
Hello,
Please write correctly.
g(x)= (2x+3)/(x+1) to be written like a/(x+p) + q
It is very simple!
(2x+3)/(x+1)= [(2x+2)+1]/(x+1)= (2(x+1)+1)/(x+1)= 2+1/(x+1)
Answer:
the 2nd one
Step-by-step explanation:
mecause its new=original