Answer:
The area of the square lawn is 
Step-by-step explanation:
Part 7)
Let
x ----> the length side of the square lawn in meters
we know that
The area of the path is equal to
----> equation A
----> equation B
so
Solve for x
The area of the square lawn is
substitute the value of x
Answer:
x =417.6
Step-by-step explanation:
0.5x+78.2=287
Subtract 78.2 from each side
0.5x+78.2-78.2=287-78.2
.5x =208.8
Divide each side by .5
.5x/.5 = 280.8/.5
x =417.6
The answer is -8
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Explanation:
There are two ways to get this answer
Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8
-----------------------
The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4
g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8
Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8
Regardless of which method you use, the answer is -8
