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never [62]
2 years ago
11

I need help with this

Mathematics
1 answer:
fomenos2 years ago
5 0

Answer:

B

Step-by-step explanation:

It's B

3^5 = 243

so the 5th root of 243 is 3

(x^7)^(1/5) = x^(7/5)

(y^10)^(1/5) = 7 ^(10/5) = 7^2

z^(21)^(1/5) = z^(21/5)

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Pls solve q no. 7. I need it urgently. Tomorrow is my exam.
FinnZ [79.3K]

Answer:

The area of the square lawn is 784\ m^2

Step-by-step explanation:

Part 7)

Let

x ----> the length side of the square lawn in meters

we know that

The area of the path is equal to

A=(x+2+2)^2-x^2

A=(x+4)^2-x^2 ----> equation A

A=240\ m^2 ----> equation B

so

240=(x+4)^2-x^2

Solve for x

240=(x^2+8x+16)-x^2

240=8x+16

8x=240-16

8x=224

x=28\ m

The area of the square lawn is

A=x^2

substitute the value of x

A=28^2=784\ m^2

3 0
2 years ago
Elbert made 48% of the shots he took during the basketball game.If he attempted 25 shots, how many times did he score?
mariarad [96]
0.48*25= 12...he scored 12 times
3 0
3 years ago
Solve for x.<br><br> 0.5x+78.2=287
Alona [7]

Answer:

x =417.6

Step-by-step explanation:

0.5x+78.2=287

Subtract 78.2 from each side

0.5x+78.2-78.2=287-78.2

.5x =208.8

Divide each side by .5

.5x/.5 = 280.8/.5

x =417.6

8 0
2 years ago
To find the range you take the big number and subtract the small number.True False
statuscvo [17]

Answer:

True

Please give Brainliest

7 0
2 years ago
Let g(x) = 2x and h(x)= x^2 -4. find (g o h)(0)
finlep [7]
The answer is -8

====================================================

Explanation:

There are two ways to get this answer

Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8

-----------------------

The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4

g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8

Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8

Regardless of which method you use, the answer is -8

5 0
3 years ago
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