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lisabon 2012 [21]
3 years ago
13

What is the solution of the system of equations? y = –3x + 8 y = –5x – 2

Mathematics
2 answers:
jekas [21]3 years ago
6 0
y=-3x+8 \\ y=-5x-2 \\  \\ -3x+8=-5x-2 \\ -3x+5x=-2-8 \\ 2x=-10 \\ x=- \frac{10}{2}  \\ x=-5 \\ y=-3(-5)+8=15+8=23  \\ \\ \boxed{-5,23}
xxMikexx [17]3 years ago
4 0
y=-3x+8 \\ y=-5x-2 \\  \\ -3x+8=-5x-2 \\ 2x=-10 \\ x= \frac{-10}{2} \\ x=-5 \\  \\ y=-3(-5)+8 \\ y=15+8 \\  y=23\\  \\ \boxed{(-5,23)}
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8x+12-8x+15+15x-22-x
mixas84 [53]
The answer would be 14x+5 I’m pretty sure
5 0
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Al fotocopiar una credencial, primero se amplia al triple y posteriormente la copia resultante se reduce a la mitad. ¿Cual es el
ad-work [718]
Using google translate: 
When photocopying a credential, it is first enlarged to triple and subsequently the resulting copy is halved. What is the final effect on the original credential? If the credentials is a rectangle of 10 by 6 cm. What area will you have in the first photocopy? And in the second?

Original: 10 by 6 cm  ;  Area = length * width = 10 x 6 = 60 cm²

first copy: enlarged to triple
10 x 3 = 30 
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30 x 18 = 540 cm²

second copy: halved
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4 0
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Given the function h(x)=-x^2-5x+14 determine the average rate of change of the function over the interval -9
Juli2301 [7.4K]

Answer:

The average rate of change of the function over the interval is of 6.

Step-by-step explanation:

Average rate of change:

The average rate of change of a function h(x) over an interval [a,b] is given by:

A = \frac{h(b)-h(a)}{b-a}

In this question:

Over the interval [-9,-2], so a = -9, b = -2, b - a = -2 -(-9) = 7

The function is:

h(x) = -x^2 - 5x + 14

h(-9) = -9^2 -5(-9) + 14 = -81 + 45 + 14 = -22

h(-2) = -2^2 -5(-2) + 14 = -4 + 10 + 14 = 20

Then

A = \frac{h(-2)-h(-9)}{7} = \frac{20-(-22)}{7} = \frac{42}{7} = 6

The average rate of change of the function over the interval is of 6.

8 0
3 years ago
Rewrite the following the form log (c) log (20) - log (5)
Dmitrij [34]

Answer:log (20/5)

Step-by-step explanation:

When subtracting logs you divide the numbers after the log

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3 years ago
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