Answer: Choice C
They should be blocked by pain resistance so the subjects are as similar as possible.
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Explanation:
The process of blocking in statistics is where we group up people in blocks, and each block is determined by a characteristic of some sort. In this case, we're grouping people up by pain resistance level. Those very resistant to pain will be in one group, while those who easily feel pain will be in another block, and so on. It might be effective to have a pain scale and sort people by that.
Blocking is done so that we eliminate unwanted variability. We are testing the effectiveness of the itching cream, so all we care about is if the itch reduces or not. We aren't worried about the levels of pain. However, it says that "Previous studies have shown the effects of treatment may vary based on a subject's pain resistance". So we group up the people by pain tolerance to help eliminate the variability of pain tolerance levels.
This is why choice C is the final answer.
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Extra info:
- Choice A is false because a person's name doesn't have anything to do with if the treatment works or not.
- Choice B is false because we weren't given any info to indicate it being true. It may be true, but we simply don't have enough info to confirm it.
- Choice C is false for similar reasons as choice B.
Answer:
![\frac{1}{27}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B27%7D)
Step-by-step explanation:
![3^{-3}\\=\frac{1}{3}^{3}\\=\frac{1}{27}](https://tex.z-dn.net/?f=3%5E%7B-3%7D%5C%5C%3D%5Cfrac%7B1%7D%7B3%7D%5E%7B3%7D%5C%5C%3D%5Cfrac%7B1%7D%7B27%7D)
Answer:
Price per bottle is 1.5 or $1.50
Step-by-step explanation:
To get price per unit, you just divide the amount of money spent by the items purchased. 9/6 = 1.5
X = 20
Isolate the variable by dividing each side by factors that don't contain the variable.
x
=
20
Answer:
![\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%5C%20%5C%20%5C%203x%5E2-20x%2B37%5C%20%5C%20%5C%20%7D)
Step-by-step explanation:
Hello,
a and b are the zeros, we can say that
![f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)](https://tex.z-dn.net/?f=f%28x%29%3D3%28x%5E2-%5Cdfrac%7B4%7D%7B3%7Dx%2B%5Cdfrac%7B5%7D%7B3%7D%29%20%3D%203%28x-a%29%28x-b%29%3D3%28x-%28a%2Bb%29x%2Bab%29)
So we can say that
![a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}](https://tex.z-dn.net/?f=a%2Bb%3D%5Cdfrac%7B4%7D%7B3%7D%5C%5Cab%3D%5Cdfrac%7B5%7D%7B3%7D)
Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b
for instance we can write
![(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab](https://tex.z-dn.net/?f=%28x-2a-3b%29%28x-3a-2b%29%3Dx%5E2-%282a%2B3b%2B3a%2B2b%29x%2B%282a%2B3b%29%283a%2B2b%29%5C%5C%3D%20x%5E2-5%28a%2Bb%29x%2B6a%5E2%2B6b%5E2%2B9ab%2B4ab)
and we can notice that
so
![(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab](https://tex.z-dn.net/?f=%28x-2a-3b%29%28x-3a-2b%29%3Dx%5E2-5%28a%2Bb%29x%2B6%5B%28a%2Bb%292-2ab%5D%2B13ab%5C%5C%3D%20x%5E2-5%28a%2Bb%29x%2B6%28a%2Bb%29%5E2%2Bab)
it comes
![x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}](https://tex.z-dn.net/?f=x%5E2-5%2A%5Cdfrac%7B4%7D%7B3%7Dx%2B6%28%5Cdfrac%7B4%7D%7B3%7D%29%5E2%2B%5Cdfrac%7B5%7D%7B3%7D)
multiply by 3
![3x^2-20x+2*16+5=3x^2-20x+37](https://tex.z-dn.net/?f=3x%5E2-20x%2B2%2A16%2B5%3D3x%5E2-20x%2B37)