How do i rewrite a fraction?
2 answers:
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If you know that
then it's possible to rewrite the given limit so that it resembles the one above. Then the limit itself would be some expression involving .
For starters, we have
Let . Then as
, we also have
, and
So in terms of , the limit is equivalent to
Now use some of the properties of limits: the above is the same as
The first limit is trivial; , so its value is 1. The second limit comes out to
To see why this is the case, replace , so that
as
, and
Then the limit we're talking about has a value of
# # #
Another way to do this without knowing the definition of as given above is to take apply exponentials and logarithms, but you need to know about L'Hopital's rule. In particular, write
(where the notation means , just to get everything on one line).
Recall that
if is continuous at
.
is continuous everywhere, so we have
For the remaining limit, write
Now as , both the numerator and denominator approach 0, so we can try L'Hopital's rule. If the limit exists, it's equal to
and our original limit comes out to the same value as before, .
Answer:
d. -1.9; not unusual
Step-by-step explanation:
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that;
.
So
A z-score of -1.9 is higher than -2 and lower than 2, so it is not unusual.
So the correct answer is:
d. -1.9; not unusual