Answer:
arturo earned the ,most
Step-by-step explanation:
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
To find the probability of two independent events, multiply the probability of the first event by the probability of the second event
this only has a variable on one side
-8 = -9 + b/3
add 9 to both sides
1 = b/3
multiply by 3 to both sides
3 = b
check:
-8 = -9 + 3/3
-8 = -9 +1
-8 =-8
