To solve for AC in the given inscribed angle we proceed as follows:
An inscribed angle is an angle with its vertex "on" the circle formed by two intersecting chords as in our drawing. Thus here we shall use the formula:
Inscribed Angle=1/2 intercepted Arc
thus
m∠ABC=1/2mAC
thus plugging in our values we shall have:
4x-3.5=1/2(4x+17)
4x-3.5=2x+8.5
solving simplifying and solving for x we obtain
4x-2x=8.5+3.5
2x=12
hence
x=12/2
x=6°
Answer:
B.)The volume of the triangular prism is not equal to the volume of the cylinder.
Step-by-step explanation:
Let A be the cross-sectional area of both congruent right triangular prism and right cylinder.
Since the prism has height 2 units, its volume V₁ = 2A.
Since the cylinder has height 6 units, its volume is V₂ = 6A
Dividing V₁/V₂ = 2A/6A =1/3
V₁ = V₂/3.
The volume of the prism is one-third the volume of the cylinder.
So, since the volume of the prism is neither double nor half of the volume of the cylinder nor is it equal to the volume of the cylinder, B is the correct answer.
So, the volume of the triangular prism is not equal to the volume of the cylinder.
Answer:
X-14 / 2 = 24
Step-by-step explanation:
X-14 / 2 = 24
X-14 / 2 = 24
You can converte them to a common denominator like 6. 1/2 would be 3/6. 2/3 would be 4/6.
4 and a half ducks.
That's pretty much the answer.
