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2 years ago

Write a 2 column proof showing segment ML is congruent to Segment OL.

Mathematics

1 answer:

Allisa [31]2 years ago

6 0

The statements and Reasons correspond to each other by the numbers listed.

Let C = congruent in place of the congruent symbol. I don't have it on my keyboard.

Statements

1. Side MN C Side ON.

2. LN is C to LN.

3. Angle LNM is C to angle ONL

4. Angle NML is C to angle NOL

5. ML is C to OL

Reasons

1. Given

2. Reflexive Property

3. Definition of angle bisector

4. SAS Postulate

5. Side NL cuts MO in half

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Steve is buying gas for $2.50 per gallon. He wants to buy 20 gallons for his truck. How much does he spend total?

lana [24]

Answer:

Step-by-step explanation:

gas costs 2.50 per gallon....if he wants to buy 20 gallons, then he is gonna have to spend : (2.50 * 20) = $ 50 <==

3 0

3 years ago

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Please help again! Same thing!

cestrela7 [59]

Answer:

a = - 3, b = 5

Step-by-step explanation:

To rationalise the denominator multiply the numerator/ denominator by $\sqrt{2}$

= $\frac{\sqrt{2}(10-\sqrt{18}) }{(\sqrt{2})^2 }$

= $\frac{10\sqrt{2}-\sqrt{36} }{2}$

= $\frac{10\sqrt{2}-6 }{2}$

= 5 $\sqrt{2}$ - 3

= - 3 + 5 $\sqrt{2}$ ← in the form a + b $\sqrt{2}$

with a = - 3 and b = 5

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3 years ago

Express the integral as an iterated integral in six different ways, where E is the solid bounded by y=4-x^2-4z^2 and y=0

zmey [24]

Assuming you need the integral expressing the volume of $E$ , the easiest setup is to integrate with respect to $y$ first.

This is done with either

$\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_{-2}^2\int_0^{4-x^2-z^2}\mathrm dy\,\mathrm dx\,\mathrm dz$
$\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_{-2}^2\int_0^{4-x^2-z^2}\mathrm dy\,\mathrm dz\,\mathrm dx$

Thanks to symmetry, integrating with respect to either $x$ or $z$ first will be nearly identical.

First, with respect to $x$ :

$\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_0^4\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-z^2}}\mathrm dx\,\mathrm dy\,\mathrm dz$
$\displaystyle\iiint_E\mathrm dV=\int_0^4\int_{-2}^2\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-z^2}}\mathrm dx\,\mathrm dz\,\mathrm dy$

Next, with respec to $z$ :

$\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_0^4\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-x^2}}\mathrm dz\,\mathrm dy\,\mathrm dx$
$\displaystyle\iiint_E\mathrm dV=\int_0^4\int_{-2}^2\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-x^2}}\mathrm dz\,\mathrm dx\,\mathrm dy$

5 0

3 years ago

Find volume of this prism

attashe74 [19]

Answer:

324 km²

Step-by-step explanation:

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width of base = 9 km

height = 12 km

To find the volume of the pyramid, we plug in these given values into the formula

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3 years ago

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Katena32 [7]

So all the angles on one side should equal 180.
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4 0

4 years ago