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Anarel [89]
2 years ago
14

Write a 2 column proof showing segment ML is congruent to Segment OL.

Mathematics
1 answer:
Allisa [31]2 years ago
6 0

The statements and Reasons correspond to each other by the numbers listed.

Let C = congruent in place of the congruent symbol. I don't have it on my keyboard.

Statements

1. Side MN C Side ON.

2. LN is C to LN.

3. Angle LNM is C to angle ONL

4. Angle NML is C to angle NOL

5. ML is C to OL

Reasons

1. Given

2. Reflexive Property

3. Definition of angle bisector

4. SAS Postulate

5. Side NL cuts MO in half

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Steve is buying gas for $2.50 per gallon. He wants to buy 20 gallons for his truck. How much does he spend total?​
lana [24]

Answer:

Step-by-step explanation:

gas costs 2.50 per gallon....if he wants to buy 20 gallons, then he is gonna have to spend : (2.50 * 20) = $ 50 <==

3 0
3 years ago
Read 2 more answers
Please help again! Same thing!
cestrela7 [59]

Answer:

a = - 3, b = 5

Step-by-step explanation:

To rationalise the denominator multiply the numerator/ denominator by \sqrt{2}

= \frac{\sqrt{2}(10-\sqrt{18})  }{(\sqrt{2})^2 }

= \frac{10\sqrt{2}-\sqrt{36}  }{2}

= \frac{10\sqrt{2}-6 }{2}

= 5\sqrt{2} - 3

= - 3 + 5\sqrt{2} ← in the form a + b\sqrt{2}

with a = - 3 and b = 5

7 0
3 years ago
Express the integral as an iterated integral in six different ways, where E is the solid bounded by y=4-x^2-4z^2 and y=0
zmey [24]
Assuming you need the integral expressing the volume of E, the easiest setup is to integrate with respect to y first.

This is done with either

\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_{-2}^2\int_0^{4-x^2-z^2}\mathrm dy\,\mathrm dx\,\mathrm dz
\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_{-2}^2\int_0^{4-x^2-z^2}\mathrm dy\,\mathrm dz\,\mathrm dx

Thanks to symmetry, integrating with respect to either x or z first will be nearly identical.

First, with respect to x:

\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_0^4\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-z^2}}\mathrm dx\,\mathrm dy\,\mathrm dz
\displaystyle\iiint_E\mathrm dV=\int_0^4\int_{-2}^2\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-z^2}}\mathrm dx\,\mathrm dz\,\mathrm dy

Next, with respec to z:

\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_0^4\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-x^2}}\mathrm dz\,\mathrm dy\,\mathrm dx
\displaystyle\iiint_E\mathrm dV=\int_0^4\int_{-2}^2\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-x^2}}\mathrm dz\,\mathrm dx\,\mathrm dy
5 0
3 years ago
Find volume of this prism
attashe74 [19]

Answer:

324 km²

Step-by-step explanation:

The prism shown is a square pyramid

The volume of a square pyramid can be calculated by using this formula

V=lw\frac{h}{3}

where l = length of base, w = width of base and h = height

We are given the following dimensions...

length of base = 9 km

width of base = 9 km

height = 12 km

To find the volume of the pyramid, we plug in these given values into the formula

Hence,

V = 9 * 9* \frac{12}{3} \\\frac{12}{3} =4\\V = 9*9*4\\9*9=81\\81*4=324\\

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6 0
3 years ago
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Katena32 [7]
So all the angles on one side should equal 180.
50+55= 105
180-105=75
12x+3=75
12x=72
12*6=72
x=6
4 0
4 years ago
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