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spin [16.1K]
3 years ago
10

How do you write the equation of this description: the graph of a parabola has a vertex of (2,3) and vertically stretched by 3

Mathematics
1 answer:
Mademuasel [1]3 years ago
3 0

The equation of parabola is  y = 3x²- 12x+ 15.

<u>Step-by-step explanation:</u>

The equation of the parabola is given as y = x².

If it has a vertex then the equation can be written as,

y = a(x-h)² + k

where (h, k ) is the vertex and a is the stretching or compressing factor.

So here the vertex is (2,3) and it is vertically stretched by 3.

So the equation is given as,

y = 3(x-2)² + 3

y = 3(x² -4x+4) + 3

 = 3x² - 12x + 12 + 3

y = 3x²- 12x+ 15 is the equation of the parabola.

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Please help! Thanks in advance​
marishachu [46]

b is the base which is given as 15 cm

h is the height given as 13 cm

A = (15 * 13) /2

A = 195/2

A = 97.5 cm^2

3 0
3 years ago
Read 2 more answers
Combine any like terms in the expression. If there are no like terms, rewrite the expression.
Llana [10]
If the 3’s were exponents then... i got 50r3

how i solved:

39r3 + 11r3 + 45s3 - 5s3 - 40s3

50r3 + 40s3 - 40s3

50r3 + 0

= 50r3
4 0
4 years ago
If x-y= -10 and x-y=2 what is the value of x
sp2606 [1]
No solution , because x-y = -10 therefore x-y can’t be -2
8 0
3 years ago
A circular fountain 10 feet in diameter has a circular walk 3 feet wide paved around it. What is the area of the walk?
Gnom [1K]
Hi there!

• Radius = \dfrac{10}{2} ft = 5 ft.

Area of the fountain = πr² = 3.14 x (5)² = 78.5 ft²

•Radius for fountain n' walk = \dfrac{10 + 3}{2} = \dfrac{13}{2} = 6.5 ft

Area of fountain n' walk = πr² = 3.14 x (6.5)² = 132. 6 ft²

| Area of th' Circular walk |

132.6 - 78.5 ft² = 54. 1 ft²
ar( Larger circle ) - ar( Smaller circle )

Hence,
The area of the walk around the fountain is 54. 1 ft²

~ Hope it helps!
7 0
3 years ago
Please help me with this ASAP
joja [24]

Answer:5

Step-by-step explanation:

It’s just 5

4 0
3 years ago
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